Morphocompletion for #4641 ⟨a, b | aababaab=bba

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aababaab ⇒ bba
2. aababbba ⇒ bbaabaab
3. bbaabaabababaab ⇒ aababbbbba
4. aababaaaababbbbba ⇒ bbabaabaabababaab
5. bbaabaabababbba ⇒ aababbbbbaabaab
6. bbabaabaabababaabababaab ⇒ aababaaaababbbbbbba
7. aababaaaababaaaababbbbbbba ⇒ bbababaabaabababaabababaab
8. bbaabaabababaaaababbbbba ⇒ aababbbbbabaabaabababaab
9. bbabaabaabababaabababbba ⇒ aababaaaababbbbbbbaabaab
10. bbababaabaabababaabababaabababaab ⇒ aababaaaababaaaababbbbbbbbba
11. aababaaaababaaaababaaaababbbbbbbbba ⇒ bbabababaabaabababaabababaabababaab
12. bbaabaabababaaaababaaaababbbbbbba ⇒ aababbbbbababaabaabababaabababaab
13. bbabaabaabababaabababaaaababbbbba ⇒ aababaaaababbbbbbbabaabaabababaab
14. bbababaabaabababaabababaabababbba ⇒ aababaaaababaaaababbbbbbbbbaabaab
15. bbabababaabaabababaabababaabababaabababaab ⇒ aababaaaababaaaababaaaababbbbbbbbbbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] aab, [3/3] baa, [3/4] bba, [3/5] bbb, [3/6] aaa
Length 4:[4/0] abab, [4/1] baba, [4/2] aaba, [4/3] abaa, [4/4] baab, [4/5] bbbb, [4/6] bbba
Length 5:[5/0] ababa, [5/1] aabab, [5/2] abaab, [5/3] babaa, [5/4] baaba, [5/5] babab, [5/6] bbbbb
Length 6:[6/0] aababa, [6/1] ababaa, [6/2] babaab, [6/3] abaaba, [6/4] bababa, [6/5] ababab, [6/6] baabab
Length 7:[7/0] ababaab, [7/1] bababaa, [7/2] baababa, [7/3] abaabab, [7/4] aababab, [7/5] abababa, [7/6] babaaba

Considering [length 2 / frequency 0] ba=c.

Step 2

Rewriting system is complete. See a, b | aababaab=bba.