| Back: | ⟨a, b | aababaab=aba⟩ |
|---|
Solved by morph:5/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aababaab ⇒ aba |
| 2. | abaabaab ⇒ aabababa |
| 3. | ababaaabab ⇒ aababababa |
| 4. | aabaabababa ⇒ abaaab |
| 5. | abaaabaabab ⇒ aababaaabba |
| 6. | abaaabababa ⇒ aabababaaab |
| 7. | abaaabbaaab ⇒ aabababaaba |
| 8. | aabababaaabab ⇒ abaaabba |
| 9. | aabababaababa ⇒ ababaaab |
| 10. | aababababaaab ⇒ ababaaba |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 52 | lf:40,lp:5,ls:7,rf:29,rp:5,rs:3,lsrp:3,lprs:1 |
|---|---|---|---|
| [2/1] | ba | 36 | lf:33,ls:3,rf:26,rs:7 |
| [2/2] | aa | 30 | lf:25,lp:5,rf:17,rp:5 |
| [2/3] | bb | 1 | lf:1,rf:2,a:5 |
| [3/0] | aba | 40 | lf:32,lp:5,ls:3,rf:24,rp:5,rs:5,re:1,lsrp:2,lprs:3 |
| [3/1] | aab | 27 | lf:18,lp:5,ls:4,rf:12,rp:5,rs:3,lsrp:2,lprs:2 |
| [3/2] | bab | 20 | lf:17,ls:3,rf:12 |
| [3/3] | baa | 13 | lf:13,rf:7 |
| [3/4] | aaa | 7 | lf:7,rf:5,a:2 |
| [3/5] | bba | 1 | lf:1,rf:2,rs:2,a:5 |
| [3/6] | abb | 1 | lf:1,rf:2,a:5 |
| [4/0] | abab | 21 | lf:17,lp:1,ls:3,rf:12,rp:2 |
| [4/1] | aaba | 18 | lf:13,lp:5,rf:7,rp:5,rs:2,lprs:1 |
| [4/2] | baba | 17 | lf:14,ls:3,rf:12,rs:2 |
| [4/3] | abaa | 16 | lf:12,lp:4,rf:7,rp:2 |
| [4/4] | aaab | 9 | lf:7,ls:2,rf:5,rs:3,a:2 |
| [4/5] | baab | 8 | lf:6,ls:2,rf:2 |
| [4/6] | baaa | 7 | lf:7,rf:5,a:2 |
| [5/0] | ababa | 18 | lf:14,lp:1,ls:3,rf:12,rp:2,rs:2,lsrp:1,lprs:1 |
| [5/1] | aabab | 17 | lf:10,lp:4,ls:3,rf:5,rp:5,lsrp:2 |
| [5/2] | baaab | 9 | lf:7,ls:2,rf:5,rs:3,a:2 |
| [5/3] | abaab | 9 | lf:6,lp:1,ls:2,rf:2 |
| [5/4] | abaaa | 9 | lf:6,lp:3,rf:5,rp:2,a:2 |
| [5/5] | babab | 6 | lf:6,rf:5,a:1 |
| [5/6] | babaa | 5 | lf:5,rf:5 |
| [6/0] | aababa | 12 | lf:7,lp:4,ls:1,rf:5,rp:5 |
| [6/1] | abaaab | 10 | lf:6,lp:3,ls:1,rf:5,rp:2,rs:3,re:1,lprs:1,a:2 |
| [6/2] | bababa | 8 | lf:6,ls:2,rf:5,rs:2,a:1 |
| [6/3] | ababab | 6 | lf:6,rf:5,a:1 |
| [6/4] | ababaa | 6 | lf:5,lp:1,rf:5,rp:2 |
| [6/5] | abaaba | 5 | lf:4,lp:1,rf:2,rs:2,a:1 |
| [6/6] | aabaab | 5 | lf:3,lp:1,ls:1,a:1 |
| [7/0] | abababa | 8 | lf:6,ls:2,rf:5,rs:2,a:1 |
| [7/1] | aababab | 8 | lf:5,lp:3,rf:4,rp:4,a:1 |
| [7/2] | abaaaba | 6 | lf:4,lp:2,a:3 |
| [7/3] | baaabab | 5 | lf:3,ls:2,a:3 |
| [7/4] | babaaab | 4 | lf:3,ls:1,rf:3,rs:2,a:3 |
| [7/5] | ababaaa | 4 | lf:3,lp:1,rf:3,rp:1,a:3 |
| [7/6] | abaabab | 4 | lf:3,ls:1,a:2 |
Considering [length 5 / frequency 1] aabab=c.
Rewriting system is complete. See ⟨a, b | aababaab=aba⟩.