Morphocompletion for #4637 ⟨a, b | aababaab=aba

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aababaab ⇒ aba
2. abaabaab ⇒ aabababa
3. ababaaabab ⇒ aababababa
4. aabaabababa ⇒ abaaab
5. abaaabaabab ⇒ aababaaabba
6. abaaabababa ⇒ aabababaaab
7. abaaabbaaab ⇒ aabababaaba
8. aabababaaabab ⇒ abaaabba
9. aabababaababa ⇒ ababaaab
10. aababababaaab ⇒ ababaaba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] aab, [3/2] bab, [3/3] baa, [3/4] aaa, [3/5] bba, [3/6] abb
Length 4:[4/0] abab, [4/1] aaba, [4/2] baba, [4/3] abaa, [4/4] aaab, [4/5] baab, [4/6] baaa
Length 5:[5/0] ababa, [5/1] aabab, [5/2] abaaa, [5/3] baaab, [5/4] abaab, [5/5] babab, [5/6] babaa
Length 6:[6/0] aababa, [6/1] abaaab, [6/2] bababa, [6/3] ababaa, [6/4] ababab, [6/5] abaaba, [6/6] aabaab
Length 7:[7/0] abababa, [7/1] aababab, [7/2] abaaaba, [7/3] baaabab, [7/4] ababaaa, [7/5] babaaab, [7/6] abaabab

Considering [length 5 / frequency 0] ababa=c.

Step 2

Rewriting system is complete. See a, b | aababaab=aba.