Morphocompletion for #4631 ⟨a, b | aabaabba=baa

Solved by morph:2/1,5/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaabba ⇒ baa
2. aabaabbbaa ⇒ babaa
3. aabaabbbbaa ⇒ babbaa
4. aabaabbbabaa ⇒ bababaa
5. aabaabbbbbaa ⇒ babbbaa
6. aabaabbbabbaa ⇒ bababbaa
7. aabaabbbbabaa ⇒ babbabaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] bb, [2/2] ba, [2/3] ab
Length 3:[3/0] aab, [3/1] baa, [3/2] bbb, [3/3] bba
Length 4:[4/0] aaba, [4/1] abaa, [4/2] bbaa, [4/3] baab
Length 5:[5/0] aabaa, [5/1] baabb, [5/2] abaab, [5/3] bbbaa
Length 6:[6/0] aabaab, [6/1] abaabb, [6/2] baabbb, [6/3] bbbbaa

Considering [length 2 / frequency 1] bb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. bc ⇒ cb
2. aabaaca ⇒ baa
3. aabaaccaa ⇒ bacaa
4. aabaacccaa ⇒ baccaa
5. aabaaccacaa ⇒ bacacaa
6. aabaaccccaa ⇒ bacccaa
7. bb ⇒ c
8. aabaacbaa ⇒ babaa
9. aabaaccbaa ⇒ bacbaa
10. aabaaccabaa ⇒ bacabaa
11. aabaacccbaa ⇒ baccbaa
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] cc, [2/3] ab, [2/4] ac, [2/5] ca, [2/6] cb
Length 3:[3/0] aab, [3/1] baa, [3/2] aba, [3/3] aac, [3/4] caa, [3/5] acc, [3/6] cca
Length 4:[4/0] aaba, [4/1] abaa, [4/2] baac, [4/3] aacc, [4/4] cbaa, [4/5] ccaa, [4/6] accc
Length 5:[5/0] aabaa, [5/1] abaac, [5/2] baacc, [5/3] ccbaa, [5/4] cccaa, [5/5] aaccc, [5/6] aacca

Considering [length 5 / frequency 1] abaac=d.

Step 3

Rewriting system is complete. See a, b | aabaabba=baa.