Morphocompletion for #4591 ⟨a, b | aabaaaab=aba

Solved by morph:5/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaaaab ⇒ aba
2. abaaaaab ⇒ aabaaaba
3. abaaaaaab ⇒ aaabaabaa
4. abaaaaaaab ⇒ aaaababaaa
5. abaaaaaaaabab ⇒ aaaaababaaaba
6. ababaaaaaaaab ⇒ aabaaababaaaa
7. abaaaaaaaaabab ⇒ aaaaaababaabaa
8. abaaaaaaaabaab ⇒ aaaaabaabaabaa
9. aaaaababaaaabaaa ⇒ abaaaaaaaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba
Length 3:[3/0] aaa, [3/1] aba, [3/2] aab, [3/3] baa, [3/4] bab
Length 4:[4/0] aaaa, [4/1] abaa, [4/2] aaab, [4/3] baaa, [4/4] aaba, [4/5] abab, [4/6] baba
Length 5:[5/0] aaaaa, [5/1] abaaa, [5/2] aaaab, [5/3] baaaa, [5/4] aaaba, [5/5] aabab, [5/6] aabaa
Length 6:[6/0] aaaaaa, [6/1] abaaaa, [6/2] aaaaab, [6/3] baaaaa, [6/4] aaaaba, [6/5] aaabab, [6/6] aabaaa
Length 7:[7/0] abaaaaa, [7/1] aaaaaaa, [7/2] aaaaaab, [7/3] baaaaaa, [7/4] aaaaaba, [7/5] aaaabab, [7/6] ababaaa

Considering [length 5 / frequency 2] aaaab=c.

Step 2

Rewriting system is complete. See a, b | aabaaaab=aba.