Morphocompletion for #4569 ⟨a, b | aaabbbaa=baa

Solved by morph:6/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbbaa ⇒ baa
2. aaabbbbaa ⇒ bbaa
3. aaabbbabaa ⇒ babaa
4. aaabbbbbaa ⇒ bbbaa
5. aaabbbabbaa ⇒ babbaa
6. aaabbbbabaa ⇒ bbabaa
7. aaabbbbbbaa ⇒ bbbbaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] bb, [2/2] ba, [2/3] ab
Length 3:[3/0] bbb, [3/1] baa, [3/2] aaa, [3/3] bba, [3/4] abb, [3/5] aab, [3/6] bab
Length 4:[4/0] aaab, [4/1] bbaa, [4/2] bbbb, [4/3] bbba, [4/4] abbb, [4/5] aabb, [4/6] abaa
Length 5:[5/0] aaabb, [5/1] bbbaa, [5/2] aabbb, [5/3] bbbba, [5/4] babaa, [5/5] abbbb, [5/6] bbbbb
Length 6:[6/0] aaabbb, [6/1] bbbbaa, [6/2] bbabaa, [6/3] aabbbb, [6/4] aabbba, [6/5] bbbbba, [6/6] bbbaba
Length 7:[7/0] aaabbbb, [7/1] aaabbba, [7/2] bbbbbaa, [7/3] bbbabaa, [7/4] bbabbaa, [7/5] abbbbaa, [7/6] aabbbbb

Considering [length 6 / frequency 0] aaabbb=c.

Step 2

Rewriting system is complete. See a, b | aaabbbaa=baa.