| Back: | ⟨a, b | aaabbbaa=aab⟩ |
|---|
Solved by morph:5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaabbbaa ⇒ aab |
| 2. | aababbbaa ⇒ aabb |
| 3. | aabaabbbaa ⇒ aabab |
| 4. | aabbabbbaa ⇒ aabbb |
| 5. | aabbaabbbaa ⇒ aabbab |
| 6. | aabababbbaa ⇒ aababb |
| 7. | aabbbabbbaa ⇒ aabbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 31 | lf:17,lp:7,ls:7,rf:7,rp:7,lprp:7,lsrp:7 |
|---|---|---|---|
| [2/1] | bb | 18 | lf:18,rf:8,rs:4 |
| [2/2] | ab | 14 | lf:14,rf:10,rs:3 |
| [2/3] | ba | 14 | lf:14,rf:3 |
| [3/0] | baa | 16 | lf:9,ls:7 |
| [3/1] | aab | 15 | lf:9,lp:6,rf:7,rp:7,rs:1,re:1,lprp:6 |
| [3/2] | abb | 10 | lf:10,rf:5,rs:2 |
| [3/3] | bba | 10 | lf:10,rf:1 |
| [3/4] | bbb | 8 | lf:8,rf:3,rs:2 |
| [3/5] | bab | 5 | lf:5,rf:3,rs:2,a:1 |
| [3/6] | aba | 4 | lf:4,rf:2,a:1 |
| [4/0] | bbaa | 15 | lf:8,ls:7 |
| [4/1] | aabb | 9 | lf:6,lp:3,rf:4,rp:4,rs:1,re:1,lprp:3 |
| [4/2] | abbb | 8 | lf:8,rf:2,rs:1 |
| [4/3] | bbba | 8 | lf:8 |
| [4/4] | aaba | 6 | lf:3,lp:3,rf:2,rp:2,lprp:2,a:1 |
| [4/5] | babb | 4 | lf:4,rf:1,rs:1,a:1 |
| [4/6] | abab | 3 | lf:3,rf:2,rs:1,a:1 |
| [5/0] | bbbaa | 14 | lf:7,ls:7 |
| [5/1] | abbba | 8 | lf:8 |
| [5/2] | aabbb | 5 | lf:4,lp:1,rf:2,rp:2,rs:1,re:1,lprp:1 |
| [5/3] | babbb | 4 | lf:4,a:1 |
| [5/4] | aabab | 4 | lf:2,lp:2,rf:2,rp:2,rs:1,re:1,lprp:1,a:1 |
| [5/5] | aabba | 4 | lf:2,lp:2,rf:1,rp:1,lprp:1,a:3 |
| [5/6] | bbabb | 2 | lf:2,a:3 |
| [6/0] | abbbaa | 14 | lf:7,ls:7 |
| [6/1] | aabbba | 5 | lf:4,lp:1 |
| [6/2] | babbba | 4 | lf:4,a:1 |
| [6/3] | bbabbb | 2 | lf:2,a:3 |
| [6/4] | ababbb | 2 | lf:2,a:1 |
| [6/5] | baabbb | 2 | lf:2,a:2 |
| [6/6] | aaabbb | 2 | lf:1,lp:1 |
| [7/0] | babbbaa | 8 | lf:4,ls:4,a:1 |
| [7/1] | aabbbaa | 6 | lf:3,ls:3 |
| [7/2] | bbabbba | 2 | lf:2,a:3 |
| [7/3] | aababbb | 2 | lf:1,lp:1,a:1 |
| [7/4] | aabbabb | 2 | lf:1,lp:1,a:3 |
| [7/5] | aabbbab | 2 | lf:1,lp:1,a:6 |
| [7/6] | ababbba | 2 | lf:2,a:1 |
Considering [length 5 / frequency 0] bbbaa=c.
Rewriting system is complete. See ⟨a, b | aaabbbaa=aab⟩.