Morphocompletion for #4553 ⟨a, b | aaabbaba=baa⟩

Back:⟨a, b | aaabbaba=baa⟩

Solved by morph:6/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbaba ⇒ baa
2. aaabbabbaa ⇒ babaa
3. aaabbabbbaa ⇒ babbaa
4. aaabbabbabaa ⇒ bababaa
5. aaabbabbbbaa ⇒ babbbaa
6. aaabbabbabbaa ⇒ bababbaa
7. aaabbabbbabaa ⇒ babbabaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] bb, [2/2] ba, [2/3] ab
Length 3:[3/0] bba, [3/1] abb, [3/2] aaa, [3/3] baa, [3/4] bab, [3/5] aab, [3/6] bbb
Length 4:[4/0] aaab, [4/1] abba, [4/2] bbab, [4/3] bbaa, [4/4] babb, [4/5] aabb, [4/6] baba
Length 5:[5/0] aaabb, [5/1] abbab, [5/2] bbabb, [5/3] aabba, [5/4] bbbaa, [5/5] bbaba, [5/6] babba
Length 6:[6/0] aaabba, [6/1] abbabb, [6/2] aabbab, [6/3] bbabba, [6/4] bbabaa, [6/5] babbaa, [6/6] bbabbb
Length 7:[7/0] aaabbab, [7/1] aabbabb, [7/2] bbabbaa, [7/3] abbabba, [7/4] abbabbb, [7/5] bbabbba, [7/6] bbabbab

Considering [length 6 / frequency 2] aabbab=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbaba=baa⟩.