| Back: | ⟨a, b | aaabbaaa=aab⟩ |
|---|
Solved by morph:5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaabbaaa ⇒ aab |
| 2. | aababbaaa ⇒ aabb |
| 3. | aabaabbaaa ⇒ aabab |
| 4. | aaabbaab ⇒ aabbbaaa |
| 5. | aabbabbaaa ⇒ aabbb |
| 6. | aabbaabbaaa ⇒ aabbab |
| 7. | aabababbaaa ⇒ aababb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 37 | lf:24,lp:7,ls:6,rf:9,rp:7,rs:1,lprp:7,lsrp:6,lprs:1 |
|---|---|---|---|
| [2/1] | ab | 15 | lf:14,ls:1,rf:10,rs:3 |
| [2/2] | ba | 13 | lf:13,rf:4 |
| [2/3] | bb | 9 | lf:9,rf:7,rs:3 |
| [3/0] | aab | 16 | lf:10,lp:5,ls:1,rf:7,rp:7,rs:1,re:1,lprp:5,lsrp:1 |
| [3/1] | aaa | 16 | lf:8,lp:2,ls:6,rf:1,rs:1,lprs:1 |
| [3/2] | abb | 9 | lf:9,rf:5,rs:2 |
| [3/3] | bba | 9 | lf:9,rf:2 |
| [3/4] | baa | 9 | lf:9,rf:1 |
| [3/5] | bab | 4 | lf:4,rf:3,rs:2,a:2 |
| [3/6] | aba | 4 | lf:4,rf:2,a:2 |
| [4/0] | baaa | 12 | lf:6,ls:6,rf:1,rs:1 |
| [4/1] | abba | 9 | lf:9,rf:1 |
| [4/2] | aabb | 8 | lf:6,lp:2,rf:4,rp:4,rs:1,re:1,lprp:2 |
| [4/3] | bbaa | 8 | lf:8,rf:1 |
| [4/4] | aaba | 6 | lf:3,lp:3,rf:2,rp:2,lprp:2,a:2 |
| [4/5] | baab | 4 | lf:3,ls:1,a:1 |
| [4/6] | aaab | 4 | lf:2,lp:2 |
| [5/0] | bbaaa | 12 | lf:6,ls:6,rf:1,rs:1 |
| [5/1] | aabba | 8 | lf:6,lp:2,rf:1,rp:1,lprp:1 |
| [5/2] | abbaa | 8 | lf:8 |
| [5/3] | aaabb | 4 | lf:2,lp:2 |
| [5/4] | aabab | 4 | lf:2,lp:2,rf:2,rp:2,rs:1,re:1,lprp:1,a:2 |
| [5/5] | babba | 3 | lf:3,a:2 |
| [5/6] | bbaab | 3 | lf:2,ls:1,a:1 |
| [6/0] | abbaaa | 12 | lf:6,ls:6 |
| [6/1] | aabbaa | 6 | lf:5,lp:1 |
| [6/2] | aaabba | 4 | lf:2,lp:2 |
| [6/3] | abbaab | 3 | lf:2,ls:1,a:1 |
| [6/4] | babbaa | 3 | lf:3,a:2 |
| [6/5] | aababb | 2 | lf:1,lp:1,rf:1,rp:1,rs:1,re:1,a:2 |
| [6/6] | aabbab | 2 | lf:1,lp:1,rf:1,rp:1,rs:1,re:1,a:4 |
| [7/0] | babbaaa | 6 | lf:3,ls:3,a:2 |
| [7/1] | aabbaaa | 6 | lf:3,ls:3 |
| [7/2] | aabbaab | 4 | lf:2,lp:1,ls:1,a:1 |
| [7/3] | aaabbaa | 4 | lf:2,lp:2 |
| [7/4] | aabbabb | 2 | lf:1,lp:1,a:4 |
| [7/5] | aabaabb | 2 | lf:1,lp:1,a:3 |
| [7/6] | aababab | 2 | lf:1,lp:1,a:5 |
Considering [length 5 / frequency 0] bbaaa=c.
Rewriting system is complete. See ⟨a, b | aaabbaaa=aab⟩.