| Back: | ⟨a, b | aaababba=baa⟩ |
|---|
Solved by morph:4/1,3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaababba ⇒ baa |
| 2. | aaababbbaa ⇒ babaa |
| 3. | aaababbbbaa ⇒ babbaa |
| 4. | aaababbbabaa ⇒ bababaa |
| 5. | aaababbbbbaa ⇒ babbbaa |
| 6. | aaababbbabbaa ⇒ bababbaa |
| 7. | aaababbbbabaa ⇒ babbabaa |
| ... |
Collecting factors up to length 7, frequency 4:
| Length 2: | [2/0] aa, [2/1] bb, [2/2] ba, [2/3] ab |
|---|---|
| Length 3: | [3/0] aaa, [3/1] baa, [3/2] bbb, [3/3] bab |
| Length 4: | [4/0] aaab, [4/1] babb, [4/2] bbaa, [4/3] abab |
| Length 5: | [5/0] aaaba, [5/1] ababb, [5/2] aabab, [5/3] babbb |
| Length 6: | [6/0] aaabab, [6/1] aababb, [6/2] ababbb, [6/3] bbbbaa |
Considering [length 4 / frequency 1] babb=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | aaacaaacaaca ⇒ caa |
| 2. | aaacaaacaaccaa ⇒ cacaa |
| 3. | aaacaaacaacccaa ⇒ caccaa |
| 4. | baa ⇒ aaaca |
| 5. | bcaa ⇒ aaacaacaaacaaca |
| 6. | bacaa ⇒ aaaccaa |
| 7. | baccaa ⇒ aaacccaa |
| 8. | bacacaa ⇒ aaaccacaa |
| 9. | bacccaa ⇒ aaaccccaa |
| 10. | bacaccaa ⇒ aaaccaccaa |
| 11. | baccacaa ⇒ aaacccacaa |
| 12. | bacacacaa ⇒ aaaccacacaa |
| 13. | baccccaa ⇒ aaacccccaa |
| 14. | bacacccaa ⇒ aaaccacccaa |
| 15. | baccaccaa ⇒ aaacccaccaa |
| 16. | bacacaccaa ⇒ aaaccacaccaa |
| 17. | bacccacaa ⇒ aaaccccacaa |
| 18. | bacccccaa ⇒ aaaccccccaa |
| 19. | babc ⇒ cabb |
| 20. | babb ⇒ c |
| ... |
Collecting factors up to length 6, frequency 7:
| Length 2: | [2/0] aa, [2/1] ca, [2/2] ba, [2/3] ac, [2/4] cc, [2/5] bc, [2/6] bb |
|---|---|
| Length 3: | [3/0] caa, [3/1] bac, [3/2] aca, [3/3] cca, [3/4] acc, [3/5] cac, [3/6] ccc |
| Length 4: | [4/0] ccaa, [4/1] acaa, [4/2] bacc, [4/3] baca, [4/4] aaac, [4/5] aaca, [4/6] acca |
| Length 5: | [5/0] bacac, [5/1] cccaa, [5/2] accaa, [5/3] aaaca, [5/4] baccc, [5/5] cacaa, [5/6] bacca |
Considering [length 3 / frequency 0] caa=d.
Rewriting system is complete. See ⟨a, b | aaababba=baa⟩.