Morphocompletion for #4511 ⟨a, b | aaababaa=baa⟩

Back:⟨a, b | aaababaa=baa⟩

Solved by morph:6/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaababaa ⇒ baa
2. aaababbaa ⇒ bbaa
3. aaabababaa ⇒ babaa
4. aaababbbaa ⇒ bbbaa
5. aaabababbaa ⇒ babbaa
6. aaababbabaa ⇒ bbabaa
7. aaababbbbaa ⇒ bbbbaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] baa, [3/1] aaa, [3/2] aba, [3/3] bab, [3/4] aab, [3/5] bba, [3/6] abb
Length 4:[4/0] aaab, [4/1] abab, [4/2] bbaa, [4/3] aaba, [4/4] abaa, [4/5] babb, [4/6] baba
Length 5:[5/0] aaaba, [5/1] aabab, [5/2] babaa, [5/3] ababb, [5/4] bbbaa, [5/5] abbaa, [5/6] ababa
Length 6:[6/0] aaabab, [6/1] babbaa, [6/2] ababaa, [6/3] aababb, [6/4] ababba, [6/5] aababa, [6/6] bbbbaa
Length 7:[7/0] aaababb, [7/1] aaababa, [7/2] ababbaa, [7/3] babbbaa, [7/4] bababaa, [7/5] abbbbaa, [7/6] abbabaa

Considering [length 6 / frequency 0] aaabab=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaababaa=baa⟩.