| Back: | ⟨a, b | aaababaa=aab⟩ |
|---|
Solved by morph:5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaababaa ⇒ aab |
| 2. | aabababaa ⇒ aabb |
| 3. | aabaababaa ⇒ aabab |
| 4. | aabbbabaaaa ⇒ aababb |
| 5. | aabbababaa ⇒ aabbb |
| 6. | aabbaababaa ⇒ aabbab |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb |
|---|---|
| Length 3: | [3/0] aab, [3/1] aba, [3/2] baa, [3/3] bab, [3/4] aaa, [3/5] abb, [3/6] bba |
| Length 4: | [4/0] abaa, [4/1] baba, [4/2] aaba, [4/3] aabb, [4/4] abab, [4/5] bbab, [4/6] abba |
| Length 5: | [5/0] babaa, [5/1] ababa, [5/2] aabab, [5/3] aabba, [5/4] aabbb, [5/5] babab, [5/6] bbaba |
| Length 6: | [6/0] ababaa, [6/1] aababa, [6/2] aabbab, [6/3] aabbba, [6/4] baabab, [6/5] bababa, [6/6] aaabab |
| Length 7: | [7/0] aababaa, [7/1] bababaa, [7/2] aabbbab, [7/3] aababab, [7/4] aabbaab, [7/5] aabbaba, [7/6] baababa |
Considering [length 5 / frequency 0] babaa=c.
Rewriting system is complete. See ⟨a, b | aaababaa=aab⟩.