| Back: | ⟨a, b | aaababaa=aab⟩ |
|---|
Solved by morph:5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaababaa ⇒ aab |
| 2. | aabababaa ⇒ aabb |
| 3. | aabaababaa ⇒ aabab |
| 4. | aabbbabaaaa ⇒ aababb |
| 5. | aabbababaa ⇒ aabbb |
| 6. | aabbaababaa ⇒ aabbab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 29 | lf:17,lp:6,ls:6,rf:6,rp:6,lprp:6,lsrp:6 |
|---|---|---|---|
| [2/1] | ab | 16 | lf:16,rf:9,rs:3 |
| [2/2] | ba | 16 | lf:16,rf:3 |
| [2/3] | bb | 4 | lf:4,rf:5,rs:3,a:1 |
| [3/0] | aab | 13 | lf:8,lp:5,rf:6,rp:6,rs:1,re:1,lprp:5 |
| [3/1] | aba | 13 | lf:13,rf:2 |
| [3/2] | baa | 13 | lf:8,ls:5 |
| [3/3] | bab | 8 | lf:8,rf:3,rs:2 |
| [3/4] | aaa | 5 | lf:3,lp:1,ls:1 |
| [3/5] | abb | 3 | lf:3,rf:4,rs:2,a:1 |
| [3/6] | bba | 3 | lf:3,rf:1,a:3 |
| [4/0] | abaa | 12 | lf:7,ls:5 |
| [4/1] | baba | 8 | lf:8 |
| [4/2] | aaba | 7 | lf:5,lp:2,rf:2,rp:2,lprp:1 |
| [4/3] | aabb | 6 | lf:3,lp:3,rf:3,rp:3,rs:1,re:1,lprp:2,a:1 |
| [4/4] | abab | 6 | lf:6,rf:2,rs:1 |
| [4/5] | bbab | 2 | lf:2,rf:1,rs:1,a:3 |
| [4/6] | abba | 2 | lf:2,rf:1,a:3 |
| [5/0] | babaa | 11 | lf:6,ls:5 |
| [5/1] | ababa | 6 | lf:6 |
| [5/2] | aabab | 5 | lf:4,lp:1,rf:2,rp:2,rs:1,re:1 |
| [5/3] | aabba | 4 | lf:2,lp:2,rf:1,rp:1,lprp:1,a:3 |
| [5/4] | aabbb | 2 | lf:1,lp:1,rf:1,rp:1,rs:1,re:1,a:3 |
| [5/5] | babab | 2 | lf:2,a:1 |
| [5/6] | bbaba | 2 | lf:2,a:3 |
| [6/0] | ababaa | 10 | lf:5,ls:5 |
| [6/1] | aababa | 5 | lf:4,lp:1 |
| [6/2] | aabbab | 2 | lf:1,lp:1,rf:1,rp:1,rs:1,re:1,a:3 |
| [6/3] | aabbba | 2 | lf:1,lp:1,a:4 |
| [6/4] | baabab | 2 | lf:2,a:2 |
| [6/5] | bababa | 2 | lf:2,a:1 |
| [6/6] | aaabab | 2 | lf:1,lp:1 |
| [7/0] | aababaa | 6 | lf:3,ls:3 |
| [7/1] | bababaa | 4 | lf:2,ls:2,a:1 |
| [7/2] | aabbbab | 2 | lf:1,lp:1,a:4 |
| [7/3] | aababab | 2 | lf:1,lp:1,a:1 |
| [7/4] | aabbaab | 2 | lf:1,lp:1,a:5 |
| [7/5] | aabbaba | 2 | lf:1,lp:1,a:3 |
| [7/6] | baababa | 2 | lf:2,a:2 |
Considering [length 5 / frequency 0] babaa=c.
Rewriting system is complete. See ⟨a, b | aaababaa=aab⟩.