Morphocompletion for #4459 ⟨a, b | aaaabbaa=baa⟩

Back:⟨a, b | aaaabbaa=baa⟩

Solved by morph:6/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbaa ⇒ baa
2. aaaabbbaa ⇒ bbaa
3. aaaabbabaa ⇒ babaa
4. aaaabbbbaa ⇒ bbbaa
5. aaaabbabbaa ⇒ babbaa
6. aaaabbbabaa ⇒ bbabaa
7. aaaabbbbbaa ⇒ bbbbaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] bb, [2/2] ba, [2/3] ab
Length 3:[3/0] aaa, [3/1] baa, [3/2] bba, [3/3] abb, [3/4] bbb, [3/5] aab, [3/6] bab
Length 4:[4/0] aaaa, [4/1] bbaa, [4/2] aabb, [4/3] aaab, [4/4] bbba, [4/5] abbb, [4/6] abba
Length 5:[5/0] aaaab, [5/1] aaabb, [5/2] bbbaa, [5/3] babaa, [5/4] abbaa, [5/5] aabbb, [5/6] aabba
Length 6:[6/0] aaaabb, [6/1] bbbbaa, [6/2] bbabaa, [6/3] aaabbb, [6/4] aaabba, [6/5] babbaa, [6/6] abbbaa
Length 7:[7/0] aaaabbb, [7/1] aaaabba, [7/2] bbbbbaa, [7/3] bbbabaa, [7/4] bbabbaa, [7/5] abbbbaa, [7/6] abbabaa

Considering [length 6 / frequency 0] aaaabb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaabbaa=baa⟩.