Morphocompletion for #4443 ⟨a, b | aaaababa=baa⟩

Back:⟨a, b | aaaababa=baa⟩

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaababa ⇒ baa
2. aaaababbaa ⇒ babaa
3. aaaababbbaa ⇒ babbaa
4. aaaababbabaa ⇒ bababaa
5. aaaababbbbaa ⇒ babbbaa
6. aaaababbabbaa ⇒ bababbaa
7. aaaababbbabaa ⇒ babbabaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aaa, [3/1] baa, [3/2] aba, [3/3] bab, [3/4] bba, [3/5] abb, [3/6] aab
Length 4:[4/0] aaaa, [4/1] bbaa, [4/2] babb, [4/3] abab, [4/4] aaba, [4/5] aaab, [4/6] baba
Length 5:[5/0] aaaab, [5/1] aabab, [5/2] aaaba, [5/3] ababb, [5/4] bbbaa, [5/5] babba, [5/6] babaa
Length 6:[6/0] aaaaba, [6/1] aaabab, [6/2] aababb, [6/3] bbabaa, [6/4] babbaa, [6/5] ababbb, [6/6] ababba
Length 7:[7/0] aaaabab, [7/1] aaababb, [7/2] aababbb, [7/3] aababba, [7/4] bbbabaa, [7/5] bbabbaa, [7/6] babbbaa

Considering [length 7 / frequency 0] aaaabab=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaababa=baa⟩.