| Back: | ⟨a, b | aaaababa=aab⟩ |
|---|
Solved by morph:5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaaababa ⇒ aab |
| 2. | aabaababa ⇒ aabb |
| 3. | aabaaababa ⇒ aabab |
| 4. | aaaababb ⇒ aabababa |
| 5. | aabbaababa ⇒ aabbb |
| 6. | aabbaaababa ⇒ aabbab |
| 7. | aababaababa ⇒ aababb |
| 8. | aababaaababa ⇒ aababab |
| 9. | aabbbaababa ⇒ aabbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ba | 34 | lf:26,ls:8,rf:8,rs:1 |
|---|---|---|---|
| [2/1] | aa | 32 | lf:23,lp:9,rf:9,rp:9,lprp:9 |
| [2/2] | ab | 27 | lf:27,rf:16,rs:4 |
| [2/3] | bb | 6 | lf:5,ls:1,rf:8,rs:4,a:4 |
| [3/0] | aba | 31 | lf:23,ls:8,rf:7,rs:1 |
| [3/1] | aab | 23 | lf:16,lp:7,rf:9,rp:9,rs:1,re:1,lprp:7 |
| [3/2] | bab | 11 | lf:11,rf:7,rs:3 |
| [3/3] | aaa | 9 | lf:7,lp:2 |
| [3/4] | baa | 7 | lf:7,a:1 |
| [3/5] | abb | 5 | lf:4,ls:1,rf:5,rs:2,a:4 |
| [3/6] | bba | 3 | lf:3,rf:1,a:10 |
| [4/0] | baba | 18 | lf:10,ls:8,rf:3,rs:1 |
| [4/1] | aaba | 17 | lf:13,lp:4,rf:4,rp:4,lprp:3 |
| [4/2] | abab | 11 | lf:11,rf:6,rs:2 |
| [4/3] | aabb | 6 | lf:3,lp:3,rf:4,rp:4,rs:1,re:1,lprp:3,a:4 |
| [4/4] | aaab | 5 | lf:5 |
| [4/5] | baab | 4 | lf:4,a:4 |
| [4/6] | abaa | 4 | lf:4,a:1 |
| [5/0] | ababa | 18 | lf:10,ls:8,rf:3,rs:1 |
| [5/1] | aabab | 13 | lf:11,lp:2,rf:4,rp:4,rs:1,re:1,lprp:2 |
| [5/2] | aaaba | 5 | lf:5 |
| [5/3] | aabba | 4 | lf:2,lp:2,rf:1,rp:1,lprp:1,a:10 |
| [5/4] | baaba | 4 | lf:4,a:4 |
| [5/5] | aaaab | 4 | lf:2,lp:2 |
| [5/6] | aabaa | 4 | lf:2,lp:2,a:1 |
| [6/0] | aababa | 20 | lf:10,lp:2,ls:8,rf:2,rp:2,lprp:1,lsrp:1 |
| [6/1] | aaabab | 5 | lf:5 |
| [6/2] | baabab | 4 | lf:4,a:4 |
| [6/3] | aabbaa | 4 | lf:2,lp:2,a:10 |
| [6/4] | aaaaba | 4 | lf:2,lp:2 |
| [6/5] | baaaba | 3 | lf:3,a:1 |
| [6/6] | aababb | 2 | lf:1,ls:1,rf:1,rp:1,rs:1,re:1,a:5 |
| [7/0] | baababa | 8 | lf:4,ls:4,a:4 |
| [7/1] | aaababa | 8 | lf:4,ls:4 |
| [7/2] | aaaabab | 4 | lf:2,lp:2 |
| [7/3] | aababaa | 4 | lf:2,lp:2,a:2 |
| [7/4] | baaabab | 3 | lf:3,a:1 |
| [7/5] | bbaabab | 2 | lf:2,a:12 |
| [7/6] | aaababb | 2 | lf:1,ls:1,a:34 |
Considering [length 5 / frequency 0] ababa=c.
Rewriting system is complete. See ⟨a, b | aaaababa=aab⟩.