Morphocompletion for #4356 ⟨a, b | abbbabbba=ab⟩

Back:⟨a, b | abbbabbba=ab⟩

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbab ⇒ abbbba
2. abbbbab ⇒ abbbbba
3. abbbbbbaa ⇒ ab
4. abbbbbab ⇒ abbbbbba
5. abbbbbbbaa ⇒ abb
6. abbbbbbab ⇒ abbbbbbba
7. abbbbbbbbaa ⇒ abbb
8. abbbbbbbbbaa ⇒ abbbb
9. abbbbbbbbbbaa ⇒ abbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] aa, [2/3] ba
Length 3:[3/0] bbb, [3/1] abb, [3/2] baa, [3/3] bba, [3/4] bab
Length 4:[4/0] bbbb, [4/1] abbb, [4/2] bbaa, [4/3] bbba, [4/4] bbab
Length 5:[5/0] bbbbb, [5/1] abbbb, [5/2] bbbaa, [5/3] bbbab, [5/4] bbbba, [5/5] abbba
Length 6:[6/0] bbbbbb, [6/1] abbbbb, [6/2] bbbbaa, [6/3] bbbbba, [6/4] bbbbab, [6/5] abbbba
Length 7:[7/0] abbbbbb, [7/1] bbbbbbb, [7/2] bbbbbaa, [7/3] bbbbbba, [7/4] bbbbbab, [7/5] abbbbba

Considering [length 7 / frequency 0] abbbbbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbbabbba=ab⟩.