Morphocompletion for #4340 ⟨a, b | abbabaaab=aa⟩

Solved by morph:5/3,4/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbabaaab ⇒ aa
2. abbabaaaa ⇒ aababaaab
3. aaaaabbbabaaab ⇒ aaaaaba
4. aaaaabbbabaaaa ⇒ aaaaabababaaab
5. aaabaaabbbabaaab ⇒ aaabaaaba
6. aababaaabbbabaaab ⇒ aababaaaba
7. aaabaaababbbabaaab ⇒ aaabaaababa
8. aababaaababbbabaaab ⇒ aababaaababa
...

Collecting factors up to length 7 / frequency 4:

[2/0]aa48lf:40,lp:6,ls:2,rf:28,rp:8,rs:1,re:1,lprp:6,lsrp:2
[2/1]ab38lf:30,lp:2,ls:6,rf:20,rs:2,lprs:1
[2/2]ba24lf:24,rf:18,rs:5
[2/3]bb14lf:14
[3/0]aaa28lf:22,lp:4,ls:2,rf:14,rp:4,lprp:4,lsrp:1
[3/1]aab24lf:16,lp:2,ls:6,rf:13,rp:3,rs:2,lprp:2,lsrp:2
[3/2]aba16lf:16,rf:18,rs:5
[3/3]baa12lf:12,rf:6
[4/0]aaab22lf:14,lp:2,ls:6,rf:10,rp:2,rs:2,lprp:2,lsrp:2
[4/1]baaa12lf:12,rf:6
[4/2]abaa12lf:12,rf:6
[4/3]aaaa10lf:6,lp:2,ls:2,rf:4,rp:2,lprp:2,lsrp:1,a:1
[5/0]baaab16lf:10,ls:6,rf:6,rs:2
[5/1]abaaa12lf:12,rf:6
[5/2]babaa10lf:10,rf:4
[5/3]bbaba8lf:8
[6/0]abaaab16lf:10,ls:6,rf:6,rs:2
[6/1]babaaa10lf:10,rf:4
[6/2]bbabaa8lf:8
[6/3]bbbaba6lf:6,a:2

Considering [length 5 / frequency 3] bbaba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ccaab ⇒ ca
2. cccacaac ⇒ caa
3. acaab ⇒ aa
4. caaba ⇒ ccacaac
5. accacaac ⇒ aaa
6. caaaab ⇒ cccacaaa
7. bbaba ⇒ c
8. cababa ⇒ ccaac
9. aaaba ⇒ acacaac
10. ccacaacba ⇒ cacaac
11. caacacaac ⇒ cccacaaaa
12. aaaaab ⇒ accacaaa
13. aababa ⇒ acaac
14. acacaacba ⇒ aacaac
15. cccacccacaaaa ⇒ caaacaac
16. cccacccacccacaaa ⇒ caaacaacb
17. aaacacaac ⇒ accacaaaa
18. caaacaacba ⇒ cccacaaacaac
19. accacccacaaaa ⇒ aaaacaac
20. aaaacaacba ⇒ accacaaacaac
...

Collecting factors up to length 6 / frequency 7:

[2/0]aa45lf:37,lp:5,ls:3,rf:37,rp:4,rs:7,re:1,lsrp:1,lprs:2,a:2
[2/1]ac37lf:29,lp:4,ls:4,rf:31,rp:5,rs:10,lsrp:1,lprs:2,a:2
[2/2]ca36lf:31,lp:5,rf:30,rp:5,rs:1,re:1,a:2
[2/3]cc23lf:18,lp:5,rf:11,rp:5,a:3
[2/4]ba21lf:12,ls:9,a:1
[2/5]ab15lf:11,ls:4,a:1
[2/6]cb4lf:4,rf:1,rs:1,a:10
[3/0]aaa22lf:15,lp:4,ls:3,rf:13,rp:2,rs:5,re:1,lsrp:1,lprs:2,a:6
[3/1]caa21lf:17,lp:4,rf:20,rp:3,rs:1,re:1,a:2
[3/2]aca17lf:15,lp:2,rf:17,rp:2,a:2
[3/3]aac16lf:12,ls:4,rf:17,rp:1,rs:10,a:4
[3/4]cac13lf:13,rf:9,rp:1,a:6
[3/5]cca13lf:11,lp:2,rf:8,rp:2,a:3
[3/6]aba12lf:7,ls:5,a:1
[4/0]caac14lf:9,lp:1,ls:4,rf:11,rs:10,a:4
[4/1]acaa13lf:12,lp:1,rf:16,rp:1,a:2
[4/2]ccac11lf:10,lp:1,rf:7,rp:1,a:7
[4/3]aaaa10lf:6,lp:2,ls:2,rf:3,rp:1,rs:2,lsrp:1,a:11
[4/4]ccca10lf:7,lp:3,rf:3,rp:3,a:9
[4/5]caca9lf:9,rf:9,rp:1,a:6
[4/6]caaa8lf:5,lp:2,ls:1,rf:8,rp:2,rs:2,lsrp:1,lprs:1,a:11
[5/0]acaac12lf:8,ls:4,rf:10,rp:1,rs:9,re:1,a:4
[5/1]cccac10lf:7,lp:3,rf:3,rp:3,a:9
[5/2]cacaa9lf:9,rf:9,rp:1,a:6
[5/3]aacba8lf:4,ls:4,a:10
[5/4]ccaca7lf:6,lp:1,rf:7,rp:1,a:7
[5/5]caaaa6lf:3,lp:1,ls:2,rf:2,rs:2,a:11
[5/6]ababa4lf:2,ls:2,a:4

Considering [length 4 / frequency 2] ccac=d.

Step 3

Rewriting system is complete. See ⟨a, b | abbabaaab=aa⟩.