Morphocompletion for #4332 ⟨a, b | abbaabaab=aa⟩

Solved by morph:3/4. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#	Rule
1.	aabaabaab ⇒ abbaabaaa
2.	abbaabaab ⇒ aa
3.	aababbaabaaa ⇒ abbaabaaaaab
4.	aaaababaabaab ⇒ aaaabbbaabaaa
5.	abbabbaabaaa ⇒ aaaab
6.	aaaabbbaabaab ⇒ aaaaba
7.	aaaabbbabbaabaaa ⇒ aaaabaaab
8.	aaaababbbaabaab ⇒ aaaababa
9.	aaaabaabbbaabaab ⇒ aaaabaaba
10.	aaaabaaabbbaabaab ⇒ aaaabaaaba
11.	aaaababbbabbaabaaa ⇒ aaaababaaab
12.	aaaabababbbaabaab ⇒ aaaabababa
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:	[3/0] aab, [3/1] aaa, [3/2] baa, [3/3] aba, [3/4] abb, [3/5] bba, [3/6] bab
Length 4:	[4/0] baab, [4/1] aaba, [4/2] abaa, [4/3] aaaa, [4/4] bbaa, [4/5] aaab, [4/6] baaa
Length 5:	[5/0] abaab, [5/1] aaaab, [5/2] aabaa, [5/3] baaba, [5/4] bbaab, [5/5] abaaa, [5/6] abbba
Length 6:	[6/0] aabaab, [6/1] baabaa, [6/2] aaaaba, [6/3] bbaaba, [6/4] aabaaa, [6/5] abbaab, [6/6] bbbaab
Length 7:	[7/0] baabaab, [7/1] bbaabaa, [7/2] aaaabab, [7/3] baabaaa, [7/4] abbaaba, [7/5] abbbaab, [7/6] bbbaaba

Considering [length 3 / frequency 4] abb=c.

Reduction order:
- Left-to-right recursive path with deg(c) = deg(a) = 0, c < a; deg(b) = 1
Auxiliary generators:
1. abb=c

Rewriting system is complete. See ⟨a, b | abbaabaab=aa⟩.