| Back: | ⟨a, b | abbaabaab=aa⟩ |
|---|
Solved by morph:3/4. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabaabaab ⇒ abbaabaaa |
| 2. | abbaabaab ⇒ aa |
| 3. | aababbaabaaa ⇒ abbaabaaaaab |
| 4. | aaaababaabaab ⇒ aaaabbbaabaaa |
| 5. | abbabbaabaaa ⇒ aaaab |
| 6. | aaaabbbaabaab ⇒ aaaaba |
| 7. | aaaabbbabbaabaaa ⇒ aaaabaaab |
| 8. | aaaababbbaabaab ⇒ aaaababa |
| 9. | aaaabaabbbaabaab ⇒ aaaabaaba |
| 10. | aaaabaaabbbaabaab ⇒ aaaabaaaba |
| 11. | aaaababbbabbaabaaa ⇒ aaaababaaab |
| 12. | aaaabababbbaabaab ⇒ aaaabababa |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 71 | lf:57,lp:10,ls:4,rf:46,rp:10,rs:3,re:1,lprp:8,lsrp:3,lprs:2 |
|---|---|---|---|
| [2/1] | ab | 53 | lf:43,lp:2,ls:8,rf:23,rp:2,rs:4,lsrp:1,lprs:1 |
| [2/2] | ba | 35 | lf:35,rf:19,rs:5 |
| [2/3] | bb | 20 | lf:20,rf:4 |
| [3/0] | aab | 42 | lf:32,lp:2,ls:8,rf:17,rs:4,lprs:1 |
| [3/1] | aaa | 33 | lf:21,lp:8,ls:4,rf:26,rp:9,rs:2,lprp:8,lsrp:3,lprs:1,a:1 |
| [3/2] | baa | 26 | lf:26,rf:10 |
| [3/3] | aba | 22 | lf:22,rf:16,rs:5 |
| [3/4] | abb | 15 | lf:13,lp:2,rf:3,rp:2 |
| [3/5] | bba | 13 | lf:13,rf:3 |
| [3/6] | bab | 9 | lf:9,rf:4,a:2 |
| [4/0] | baab | 29 | lf:21,ls:8,rf:4 |
| [4/1] | aaba | 22 | lf:20,lp:2,rf:12,rs:3 |
| [4/2] | abaa | 16 | lf:16,rf:7 |
| [4/3] | aaaa | 16 | lf:8,lp:8,rf:11,rp:9,lprp:8,a:2 |
| [4/4] | bbaa | 10 | lf:10,rf:3 |
| [4/5] | aaab | 9 | lf:9,rf:13,rs:4,a:2 |
| [4/6] | baaa | 9 | lf:5,ls:4,rf:6,rs:2,a:1 |
| [5/0] | abaab | 19 | lf:11,ls:8,rf:1 |
| [5/1] | aaaab | 16 | lf:8,lp:8,rf:10,rp:9,rs:2,re:1,lprp:8,a:2 |
| [5/2] | aabaa | 16 | lf:15,lp:1,rf:6 |
| [5/3] | baaba | 12 | lf:12,rf:4,rs:1 |
| [5/4] | bbaab | 10 | lf:10,rf:3 |
| [5/5] | abaaa | 9 | lf:5,ls:4,rf:6,rs:2,a:1 |
| [5/6] | abbba | 7 | lf:7,rf:1,a:4 |
| [6/0] | aabaab | 19 | lf:10,lp:1,ls:8,rf:1 |
| [6/1] | baabaa | 12 | lf:12,rf:3 |
| [6/2] | aaaaba | 12 | lf:6,lp:6,rf:7,rp:7,rs:1,re:1,lprp:5,a:4 |
| [6/3] | bbaaba | 10 | lf:10,rf:3 |
| [6/4] | aabaaa | 9 | lf:5,ls:4,rf:5,rs:2,a:1 |
| [6/5] | abbaab | 6 | lf:5,lp:1,rf:2,rp:2 |
| [6/6] | bbbaab | 5 | lf:5,rf:1,a:4 |
| [7/0] | baabaab | 16 | lf:8,ls:8 |
| [7/1] | bbaabaa | 10 | lf:10,rf:3 |
| [7/2] | aaaabab | 8 | lf:4,lp:4,rf:3,rp:3,lprp:3,a:5 |
| [7/3] | baabaaa | 8 | lf:4,ls:4,rf:3,rs:2,a:1 |
| [7/4] | abbaaba | 6 | lf:5,lp:1,rf:2,rp:2 |
| [7/5] | abbbaab | 5 | lf:5,rf:1,a:4 |
| [7/6] | bbbaaba | 5 | lf:5,rf:1,a:4 |
Considering [length 3 / frequency 4] abb=c.
Rewriting system is complete. See ⟨a, b | abbaabaab=aa⟩.