Morphocompletion for #4328 ⟨a, b | abbaaaaab=bb⟩

Solved by morph:5/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbaaaabb ⇒ bbbaaaaab
2. abbaaaaab ⇒ bb
3. abbaaaababbbb ⇒ bbbaaaaaabbbb
4. abbaaaababbabb ⇒ bbbaaaaaabbabb
5. abbaaaaaabbbb ⇒ babbbb
6. abbaaaaaabbabb ⇒ babbabb
7. abbaaaaaabbbabbbb ⇒ babbbabbbb
8. abbaaaaaabbaabb ⇒ babbaabb
9. abbaaaaaabbbabbabb ⇒ babbbabbabb
10. bbbaaaaabaaaaab ⇒ abbaaabb
11. abbaaaaaabbaaabb ⇒ babbaaabb
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa54lf:54,rf:19
[2/1]bb46lf:36,lp:1,ls:9,rf:32,rp:4,rs:10,re:1,lsrp:3,lprs:1,lsrs:8
[2/2]ab43lf:31,lp:10,ls:2,rf:18,rp:1,rs:1,lsrp:1,lprs:1
[2/3]ba21lf:21,rf:17,rp:6
[3/0]abb42lf:26,lp:10,ls:6,rf:17,rp:1,rs:6,lprs:5,lsrs:5
[3/1]aaa40lf:40,rf:13
[3/2]bba18lf:18,rf:11
[3/3]aab16lf:14,ls:2,rf:6,rs:1
[3/4]baa14lf:14,rf:6
[3/5]bbb13lf:9,lp:1,ls:3,rf:11,rp:3,rs:3,lsrp:1,lsrs:3,a:1
[3/6]bab7lf:7,rf:11,rp:6,a:4
[4/0]aaaa27lf:27,rf:8
[4/1]abba25lf:15,lp:10,rf:6,rp:1
[4/2]aaab15lf:13,ls:2,rf:5,rs:1
[4/3]baaa13lf:13,rf:5
[4/4]bbaa13lf:13,rf:6
[4/5]aabb12lf:9,ls:3,rf:5,rs:3,lsrs:2,a:1
[4/6]babb10lf:7,ls:3,rf:11,rp:6,rs:3,lsrp:2,lsrs:3,a:4
[5/0]abbaa22lf:12,lp:10,rf:3,rp:1
[5/1]aaaaa15lf:15,rf:5
[5/2]aaaab14lf:12,ls:2,rf:3,rs:1
[5/3]baaaa12lf:12,rf:3
[5/4]bbaaa12lf:12,rf:5
[5/5]aaabb10lf:8,ls:2,rf:4,rs:2,lsrs:1,a:1
[5/6]bbabb8lf:5,ls:3,rf:5,rs:3,lsrs:3,a:15
[6/0]abbaaa21lf:11,lp:10,rf:2,rp:1
[6/1]aaaaab11lf:9,ls:2,rf:3,rs:1
[6/2]bbaaaa11lf:11,rf:3
[6/3]baaaaa9lf:9,rf:3
[6/4]aaaabb8lf:7,ls:1,rf:2,a:1
[6/5]aaaaaa6lf:6,rf:2,a:4
[6/6]abbabb6lf:3,ls:3,rf:3,rs:3,lsrs:3,a:15
[7/0]abbaaaa20lf:10,lp:10
[7/1]bbaaaaa8lf:8,rf:3
[7/2]aaaaaab6lf:6,rf:2,a:4
[7/3]baaaaaa6lf:6,rf:2,a:4
[7/4]aaaaabb6lf:6,rf:2,a:4
[7/5]baaaaab5lf:3,ls:2,rf:1,rs:1
[7/6]babbabb4lf:2,ls:2,rf:2,rp:1,rs:2,re:1,lsrs:1,a:15

Considering [length 5 / frequency 1] aaaaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbaaaaab=bb⟩.