Morphocompletion for #4322 ⟨a, b | ababbbbba=ab

Solved by morph:6/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbbbbaa ⇒ ab
2. ababbbbb ⇒ abbbbbba
3. abbbbbbbaa ⇒ abb
4. abbbbbbabaa ⇒ abab
5. abbbbbbbbaa ⇒ abbb
6. abbbbbbbabaa ⇒ abbab
7. abbbbbbabbaa ⇒ ababb
8. abbbbbbbbbaa ⇒ abbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] aa, [2/3] ba
Length 3:[3/0] bbb, [3/1] abb, [3/2] baa, [3/3] bba, [3/4] bab, [3/5] aba
Length 4:[4/0] bbbb, [4/1] abbb, [4/2] bbaa, [4/3] bbba, [4/4] abaa, [4/5] bbab, [4/6] babb
Length 5:[5/0] bbbbb, [5/1] abbbb, [5/2] bbbaa, [5/3] bbbba, [5/4] babaa, [5/5] bbbab, [5/6] ababb
Length 6:[6/0] abbbbb, [6/1] bbbbbb, [6/2] bbbbaa, [6/3] bbbbba, [6/4] bbabaa, [6/5] bbbbab, [6/6] ababbb
Length 7:[7/0] abbbbbb, [7/1] bbbbbaa, [7/2] bbbbbbb, [7/3] bbbbbba, [7/4] bbbabaa, [7/5] bbbbbab, [7/6] babbbbb

Considering [length 6 / frequency 0] abbbbb=c.

Step 2

Rewriting system is complete. See a, b | ababbbbba=ab.