| Back: | ⟨a, b | ababbbaba=ab⟩ |
|---|
Solved by morph:4/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | abbbbaba ⇒ ababbbab |
| 2. | ababbbaba ⇒ ab |
| 3. | abbbbbaba ⇒ abbabbbab |
| 4. | abbabbbaba ⇒ abb |
| 5. | abbbbbbaba ⇒ abbbabbbab |
| 6. | abbbabbbaba ⇒ abbb |
| 7. | abbbbbbbaba ⇒ abbbbabbbab |
| 8. | abbbbabbbaba ⇒ abbbb |
| 9. | abbbbbbbbaba ⇒ abbbbbabbbab |
| 10. | abbbbbabbbaba ⇒ abbbbb |
| 11. | abbbbbbbbbaba ⇒ abbbbbbabbbab |
| 12. | abbbbbbabbbaba ⇒ abbbbbb |
| 13. | abbbbbbbbbbaba ⇒ abbbbbbbabbbab |
| 14. | abbbbbbbabbbaba ⇒ abbbbbbb |
| 15. | abbbbbbbbbbbaba ⇒ abbbbbbbbabbbab |
| 16. | abbbbbbbbabbbaba ⇒ abbbbbbbb |
| 17. | abbbbbbbbbbbbaba ⇒ abbbbbbbbbabbbab |
| 18. | abbbbbbbbbabbbaba ⇒ abbbbbbbbb |
| 19. | abbbbbbbbbbabbbaba ⇒ abbbbbbbbbb |
| 20. | abbbbbbbbbbbabbbaba ⇒ abbbbbbbbbbb |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] bb, [2/1] ba, [2/2] ab |
|---|---|
| Length 3: | [3/0] bbb, [3/1] abb, [3/2] aba, [3/3] bab, [3/4] bba |
| Length 4: | [4/0] bbbb, [4/1] abbb, [4/2] baba, [4/3] bbab, [4/4] bbba, [4/5] babb, [4/6] abba |
| Length 5: | [5/0] bbbbb, [5/1] bbaba, [5/2] abbbb, [5/3] bbbab, [5/4] bbbba, [5/5] abbba, [5/6] babbb |
| Length 6: | [6/0] bbbbbb, [6/1] bbbaba, [6/2] abbbbb, [6/3] bbbbab, [6/4] bbbbba, [6/5] abbbab, [6/6] babbba |
| Length 7: | [7/0] bbbbbbb, [7/1] abbbbbb, [7/2] abbbaba, [7/3] bbbbaba, [7/4] bbbbbab, [7/5] bbbbbba, [7/6] babbbab |
Considering [length 4 / frequency 1] abbb=c.
Rewriting system is complete. See ⟨a, b | ababbbaba=ab⟩.