Morphocompletion for #4319 ⟨a, b | ababbbaba=ab⟩

Solved by morph:4/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abbbbaba ⇒ ababbbab
2. ababbbaba ⇒ ab
3. abbbbbaba ⇒ abbabbbab
4. abbabbbaba ⇒ abb
5. abbbbbbaba ⇒ abbbabbbab
6. abbbabbbaba ⇒ abbb
7. abbbbbbbaba ⇒ abbbbabbbab
8. abbbbabbbaba ⇒ abbbb
9. abbbbbbbbaba ⇒ abbbbbabbbab
10. abbbbbabbbaba ⇒ abbbbb
11. abbbbbbbbbaba ⇒ abbbbbbabbbab
12. abbbbbbabbbaba ⇒ abbbbbb
13. abbbbbbbbbbaba ⇒ abbbbbbbabbbab
14. abbbbbbbabbbaba ⇒ abbbbbbb
15. abbbbbbbbbbbaba ⇒ abbbbbbbbabbbab
16. abbbbbbbbabbbaba ⇒ abbbbbbbb
17. abbbbbbbbbbbbaba ⇒ abbbbbbbbbabbbab
18. abbbbbbbbbabbbaba ⇒ abbbbbbbbb
19. abbbbbbbbbbabbbaba ⇒ abbbbbbbbbb
20. abbbbbbbbbbbabbbaba ⇒ abbbbbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb140lf:140,rf:109,rs:10
[2/1]ba71lf:51,ls:20,rf:18
[2/2]ab71lf:51,lp:20,rf:38,rp:20,rs:10,re:1,lprp:20,lprs:10
[3/0]bbb110lf:110,rf:82,rs:9
[3/1]abb49lf:30,lp:19,rf:27,rp:18,rs:1,re:1,lprp:18,lprs:1
[3/2]aba42lf:21,lp:1,ls:20,rf:1,rp:1,lsrp:1
[3/3]bab31lf:31,rf:18,rs:9
[3/4]bba30lf:30,rf:17
[4/0]bbbb81lf:81,rf:57,rs:8,a:1
[4/1]abbb47lf:29,lp:18,rf:25,rp:16,rs:1,re:1,lprp:16,lprs:1
[4/2]baba40lf:20,ls:20
[4/3]bbab30lf:30,rf:17,rs:9
[4/4]bbba29lf:29,rf:16
[4/5]babb11lf:11,rf:9
[4/6]abba2lf:1,lp:1,rf:1,rp:1,a:2
[5/0]bbbbb64lf:64,rf:43,rs:7,a:4
[5/1]bbaba40lf:20,ls:20
[5/2]abbbb34lf:17,lp:17,rf:14,rp:14,rs:1,re:1,lprp:14,lprs:1,a:1
[5/3]bbbab29lf:29,rf:16,rs:9
[5/4]bbbba17lf:17,rf:6,a:1
[5/5]abbba13lf:12,lp:1,rf:10,rp:1
[5/6]babbb11lf:11,rf:9
[6/0]bbbbbb49lf:49,rf:31,rs:6,a:7
[6/1]bbbaba40lf:20,ls:20
[6/2]abbbbb30lf:15,lp:15,rf:12,rp:12,rs:1,re:1,lprp:12,lprs:1,a:4
[6/3]bbbbab17lf:17,rf:6,a:1
[6/4]bbbbba15lf:15,rf:5,a:4
[6/5]abbbab13lf:12,lp:1,rf:10,rp:1,rs:9
[6/6]babbba11lf:11,rf:9
[7/0]bbbbbbb36lf:36,rf:21,rs:5,a:9
[7/1]abbbbbb26lf:13,lp:13,rf:10,rp:10,rs:1,re:1,lprp:10,lprs:1,a:7
[7/2]abbbaba22lf:11,ls:11
[7/3]bbbbaba18lf:9,ls:9,a:1
[7/4]bbbbbab15lf:15,rf:5,a:4
[7/5]bbbbbba13lf:13,rf:4,a:7
[7/6]babbbab11lf:11,rf:9,rs:9

Considering [length 4 / frequency 1] abbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababbbaba=ab⟩.