Morphocompletion for #4319 ⟨a, b | ababbbaba=ab

Solved by morph:4/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abbbbaba ⇒ ababbbab
2. ababbbaba ⇒ ab
3. abbbbbaba ⇒ abbabbbab
4. abbabbbaba ⇒ abb
5. abbbbbbaba ⇒ abbbabbbab
6. abbbabbbaba ⇒ abbb
7. abbbbbbbaba ⇒ abbbbabbbab
8. abbbbabbbaba ⇒ abbbb
9. abbbbbbbbaba ⇒ abbbbbabbbab
10. abbbbbabbbaba ⇒ abbbbb
11. abbbbbbbbbaba ⇒ abbbbbbabbbab
12. abbbbbbabbbaba ⇒ abbbbbb
13. abbbbbbbbbbaba ⇒ abbbbbbbabbbab
14. abbbbbbbabbbaba ⇒ abbbbbbb
15. abbbbbbbbbbbaba ⇒ abbbbbbbbabbbab
16. abbbbbbbbabbbaba ⇒ abbbbbbbb
17. abbbbbbbbbbbbaba ⇒ abbbbbbbbbabbbab
18. abbbbbbbbbabbbaba ⇒ abbbbbbbbb
19. abbbbbbbbbbabbbaba ⇒ abbbbbbbbbb
20. abbbbbbbbbbbabbbaba ⇒ abbbbbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ba, [2/2] ab
Length 3:[3/0] bbb, [3/1] abb, [3/2] aba, [3/3] bab, [3/4] bba
Length 4:[4/0] bbbb, [4/1] abbb, [4/2] baba, [4/3] bbab, [4/4] bbba, [4/5] babb, [4/6] abba
Length 5:[5/0] bbbbb, [5/1] bbaba, [5/2] abbbb, [5/3] bbbab, [5/4] bbbba, [5/5] abbba, [5/6] babbb
Length 6:[6/0] bbbbbb, [6/1] bbbaba, [6/2] abbbbb, [6/3] bbbbab, [6/4] bbbbba, [6/5] abbbab, [6/6] babbba
Length 7:[7/0] bbbbbbb, [7/1] abbbbbb, [7/2] abbbaba, [7/3] bbbbaba, [7/4] bbbbbab, [7/5] bbbbbba, [7/6] babbbab

Considering [length 4 / frequency 1] abbb=c.

Step 2

Rewriting system is complete. See a, b | ababbbaba=ab.