Morphocompletion for #4311 ⟨a, b | ababbabba=ab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababb ⇒ abbba
2. abbabb ⇒ abbbba
3. abbbbbaaa ⇒ ab
4. abbbabb ⇒ abbbbba
5. abbbbbbaaa ⇒ abb
6. abbbbbabaaa ⇒ abab
7. abbbabaabba ⇒ abab
8. abbbbbbbaaa ⇒ abbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb31lf:28,ls:3,rf:12,rs:2,a:2
[2/1]ab22lf:14,lp:8,rf:10,rp:8,rs:3,re:1,lprp:8,lprs:3,a:2
[2/2]aa13lf:9,ls:4,a:9
[2/3]ba12lf:11,ls:1,rf:5,rs:3,a:2
[3/0]abb21lf:11,lp:7,ls:3,rf:5,rp:5,rs:1,re:1,lprp:4,lsrp:3,lprs:1,a:2
[3/1]bbb17lf:17,rf:7,rs:1,a:2
[3/2]bba9lf:8,ls:1,rf:3,rs:3,a:2
[3/3]aaa8lf:4,ls:4,a:23
[3/4]bab5lf:5,rf:2,rs:2,a:2
[3/5]baa5lf:5,a:9
[3/6]aba4lf:3,lp:1,rf:2,rp:2,a:2
[4/0]abbb12lf:6,lp:6,rf:4,rp:4,rs:1,re:1,lprp:2,lprs:1,a:2
[4/1]bbbb11lf:11,rf:3,a:4
[4/2]baaa8lf:4,ls:4,a:23
[4/3]babb6lf:3,ls:3,a:2
[4/4]bbba6lf:6,rf:3,rs:3,a:2
[4/5]bbab4lf:4,a:4
[4/6]abba4lf:2,lp:1,ls:1,a:4
[5/0]abbbb8lf:4,lp:4,rf:2,rp:2,a:4
[5/1]bbbbb7lf:7,rf:1,a:16
[5/2]bbaaa6lf:3,ls:3,a:23
[5/3]bbabb4lf:2,ls:2,a:4
[5/4]bbbba4lf:4,rf:2,rs:2,a:4
[5/5]abbba4lf:2,lp:2,rf:1,rp:1,rs:1,re:1,a:2
[5/6]bbbab3lf:3,a:9
[6/0]abbbbb8lf:4,lp:4,rf:1,rp:1,a:16
[6/1]bbbaaa6lf:3,ls:3,a:23
[6/2]bbbbba4lf:4,rf:1,rs:1,a:16
[6/3]abbbab4lf:2,lp:2,a:9
[6/4]bbbbbb3lf:3,a:23
[6/5]bbbbaa3lf:3,a:23
[6/6]bbbabb2lf:1,ls:1,a:16
[7/0]bbbbaaa6lf:3,ls:3,a:23
[7/1]abbbbbb4lf:2,lp:2,a:23
[7/2]abbbbba4lf:2,lp:2,rf:1,rp:1,rs:1,re:1,a:16
[7/3]bbbbbaa3lf:3,a:23
[7/4]bbbbbba2lf:2,a:23
[7/5]abbbaba2lf:1,lp:1,a:9
[7/6]bbbabaa2lf:2,a:9

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababbabba=ab⟩.