Morphocompletion for #4311 ⟨a, b | ababbabba=ab⟩

Back:⟨a, b | ababbabba=ab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababb ⇒ abbba
2. abbabb ⇒ abbbba
3. abbbbbaaa ⇒ ab
4. abbbabb ⇒ abbbbba
5. abbbbbbaaa ⇒ abb
6. abbbbbabaaa ⇒ abab
7. abbbabaabba ⇒ abab
8. abbbbbbbaaa ⇒ abbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] aa, [2/3] ba
Length 3:[3/0] abb, [3/1] bbb, [3/2] bba, [3/3] aaa, [3/4] bab, [3/5] baa, [3/6] aba
Length 4:[4/0] abbb, [4/1] bbbb, [4/2] baaa, [4/3] babb, [4/4] bbba, [4/5] bbab, [4/6] abba
Length 5:[5/0] abbbb, [5/1] bbbbb, [5/2] bbaaa, [5/3] bbabb, [5/4] bbbba, [5/5] abbba, [5/6] bbbab
Length 6:[6/0] abbbbb, [6/1] bbbaaa, [6/2] bbbbba, [6/3] abbbab, [6/4] bbbbbb, [6/5] bbbbaa, [6/6] bbbabb
Length 7:[7/0] bbbbaaa, [7/1] abbbbbb, [7/2] abbbbba, [7/3] bbbbbaa, [7/4] bbbbbba, [7/5] abbbaba, [7/6] bbbabaa

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababbabba=ab⟩.