Morphocompletion for #4297 ⟨a, b | abababaab=ba⟩

Back:⟨a, b | abababaab=ba⟩

Solved by morph:7/5. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abababaab ⇒ ba
2. ababaabba ⇒ baabaabab
3. baabaabba ⇒ abbaaabab
4. abbaaabba ⇒ babaaabab
5. ababababa ⇒ baababaab
6. baabababa ⇒ abbaabaab
7. abbaababa ⇒ babaabaab
8. baababaabab ⇒ abba
9. abbaabaabab ⇒ baba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] baa, [3/3] aab, [3/4] bba, [3/5] abb, [3/6] aaa
Length 4:[4/0] abab, [4/1] baab, [4/2] baba, [4/3] abba, [4/4] aaba, [4/5] abaa, [4/6] bbaa
Length 5:[5/0] ababa, [5/1] baaba, [5/2] aabab, [5/3] abbaa, [5/4] aabba, [5/5] abaab, [5/6] babab
Length 6:[6/0] baabab, [6/1] bababa, [6/2] ababab, [6/3] baabba, [6/4] babaab, [6/5] abbaab, [6/6] ababaa
Length 7:[7/0] abababa, [7/1] baababa, [7/2] ababaab, [7/3] abbaaba, [7/4] abaabba, [7/5] abaabab, [7/6] baabaab

Considering [length 7 / frequency 5] abaabab=c.

Step 2

Rewriting system is complete. See ⟨a, b | abababaab=ba⟩.