Morphocompletion for #4292 ⟨a, b | ababaabba=ab⟩

Back:⟨a, b | ababaabba=ab⟩

Solved by morph:6/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbaa ⇒ abbaab
2. ababbaab ⇒ ababaabb
3. abbbba ⇒ ababbb
4. ababbba ⇒ abbaabb
5. abbaabba ⇒ ababaabb
6. ababaabba ⇒ ab
7. abbbabaa ⇒ abbaabab
8. abbbbba ⇒ abbabbb
9. abbabaabba ⇒ abb
10. abbaababaabb ⇒ abbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] bb, [2/3] aa
Length 3:[3/0] abb, [3/1] bba, [3/2] aba, [3/3] baa, [3/4] bbb, [3/5] aab, [3/6] bab
Length 4:[4/0] abba, [4/1] abbb, [4/2] bbba, [4/3] baab, [4/4] abab, [4/5] bbaa, [4/6] aabb
Length 5:[5/0] abbba, [5/1] aabba, [5/2] baabb, [5/3] babaa, [5/4] abbaa, [5/5] bbbba, [5/6] abbbb
Length 6:[6/0] baabba, [6/1] abbaab, [6/2] abaabb, [6/3] bbabaa, [6/4] babaab, [6/5] ababaa, [6/6] bbbbba
Length 7:[7/0] babaabb, [7/1] abaabba, [7/2] ababaab, [7/3] bbbabaa, [7/4] abbbaba, [7/5] bbaabba, [7/6] babbaab

Considering [length 6 / frequency 0] baabba=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababaabba=ab⟩.