Morphocompletion for #4289 ⟨a, b | ababaabab=ba⟩

Solved by morph:5/0,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abababa ⇒ baaabab
2. ababaabab ⇒ ba
3. baaababba ⇒ abbaaabab
4. ababaabba ⇒ baabaabab
5. baaabbaaba ⇒ abbaaaabab
6. baabaaababb ⇒ abba
7. baaabbaaabab ⇒ abbaa
8. baaabababba ⇒ abbaabaabab
9. ababaabaabba ⇒ baaabaaababb
10. baaabbaaabba ⇒ abbaaabaabab
11. ababaabaababba ⇒ baaaababbaabab
12. abbaaaababbaba ⇒ baaabbabaaabab
13. abbaaaababbaabab ⇒ baaabbaba
14. baabaababbabaabab ⇒ ababaabbba
...

Collecting factors up to length 7 / frequency 4:

[2/0]ba67lf:51,lp:7,ls:9,rf:35,rp:7,rs:4,re:1,lsrp:5,lprs:2
[2/1]ab60lf:49,lp:7,ls:4,rf:37,rp:7,rs:8,lsrp:2,lprs:4
[2/2]aa34lf:34,rf:30,rs:1
[2/3]bb16lf:15,ls:1,rf:12,rs:1,a:2
[3/0]aba38lf:30,lp:5,ls:3,rf:18,rp:1,rs:1
[3/1]baa29lf:22,lp:7,rf:18,rp:6,rs:1,lprs:1
[3/2]bab24lf:20,ls:4,rf:13,rs:8
[3/3]aab22lf:22,rf:17
[4/0]abab27lf:18,lp:5,ls:4,rf:11,rp:1,rs:8,lsrp:1,lprs:3
[4/1]abba22lf:14,lp:2,ls:6,rf:9,rp:6,rs:1,re:1,lsrp:3,a:2
[4/2]aaba17lf:16,ls:1,rf:14
[4/3]baaa15lf:10,lp:5,rf:10,rp:5,a:1
[5/0]aabab15lf:11,ls:4,rf:10,rs:8
[5/1]baaba13lf:10,lp:2,ls:1,rf:6,rp:1
[5/2]ababa13lf:7,lp:5,ls:1,rf:1,rp:1
[5/3]baaab13lf:8,lp:5,rf:8,rp:4,a:1
[6/0]ababba9lf:6,ls:3,rf:1,a:4
[6/1]baabab8lf:5,ls:3,rf:4,rs:4
[6/2]ababaa8lf:4,lp:4,rf:1,rp:1
[6/3]baaabb7lf:4,lp:3,rf:2,rp:2,a:7

Considering [length 5 / frequency 0] aabab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. accb ⇒ c
2. aba ⇒ cc
3. abc ⇒ ccccb
4. ccbc ⇒ ba
5. abca ⇒ ccccba
6. abcc ⇒ ccba
7. aabba ⇒ cabc
8. ccabba ⇒ ccbacccb
9. accccbba ⇒ cacbc
10. aabbc ⇒ cccbacb
11. accabbc ⇒ cacbacb
12. ccbabc ⇒ abba
13. bacbc ⇒ ccbba
14. abbaa ⇒ bacccba
15. abbac ⇒ bacba
16. bacbacb ⇒ abbc
17. bacccbba ⇒ abbcc
...

Collecting factors up to length 6 / frequency 7:

[2/0]ba20lf:12,lp:3,ls:5,rf:12,rp:3,rs:7,re:1,lprs:1,a:3
[2/1]ab17lf:11,lp:6,rf:4,rp:3,a:3
[2/2]cc15lf:11,lp:3,ls:1,rf:17,rp:7,rs:2,re:1,lprp:1,lsrp:1,a:3
[2/3]bc14lf:8,ls:6,rf:4,rs:3,a:4
[2/4]ac12lf:8,lp:3,ls:1,rf:7,a:8
[2/5]cb10lf:8,ls:2,rf:13,rs:4,a:6
[2/6]bb8lf:8,rf:4,a:4
[3/0]bba10lf:6,ls:4,rf:2,rs:2,a:4
[3/1]bac9lf:5,lp:3,ls:1,rf:5,rp:2,lsrp:1,a:8
[3/2]abb8lf:6,lp:2,rf:3,rp:3,a:4
[3/3]ccb8lf:5,lp:2,ls:1,rf:8,rp:3,rs:2,a:6
[3/4]acc7lf:4,lp:3,rf:2,a:21
[3/5]abc6lf:3,lp:2,ls:1,rf:1,rs:1,a:4
[3/6]bbc4lf:2,ls:2,rf:2,rs:1,a:26
[4/0]abba8lf:4,lp:2,ls:2,rf:1,rp:1,rs:1,re:1,a:4
[4/1]bacb6lf:3,lp:2,ls:1,rf:3,rp:1,rs:2,a:8
[4/2]abbc4lf:2,ls:2,rf:2,rp:2,rs:1,re:1,a:26
[4/3]cbba4lf:2,ls:2,rf:1,rs:1,a:8
[4/4]aabb4lf:2,lp:2,a:4
[4/5]ccab3lf:2,lp:1,a:27
[4/6]accc3lf:2,lp:1,rf:2,a:21
[5/0]ccbba4lf:2,ls:2,rf:1,rp:1,rs:1,re:1,a:8
[5/1]ccabb3lf:2,lp:1,a:27
[5/2]cbabc2lf:1,ls:1,a:10
[5/3]cabbc2lf:1,ls:1,a:30
[5/4]bacba2lf:1,lp:1,rf:1,rp:1,rs:1,re:1,a:20
[5/5]cabba2lf:1,ls:1,a:27
[5/6]cbacb2lf:1,ls:1,rf:2,rs:2,a:26

Considering [length 2 / frequency 0] ba=d.

Step 3

Rewriting system is complete. See ⟨a, b | ababaabab=ba⟩.