Morphocompletion for #4280 ⟨a, b | abaabbbba=ab

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbbbaaa ⇒ ab
2. ababbbb ⇒ abbbbba
3. abaabbbb ⇒ abbbbbaa
4. abbbbbbaaa ⇒ abb
5. abbbbbabaaa ⇒ abab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] aa, [2/3] ba
Length 3:[3/0] bbb, [3/1] abb, [3/2] aaa, [3/3] aba, [3/4] baa, [3/5] bba, [3/6] bab
Length 4:[4/0] bbbb, [4/1] abbb, [4/2] baaa, [4/3] bbba, [4/4] abaa, [4/5] abab, [4/6] bbaa
Length 5:[5/0] abbbb, [5/1] bbbbb, [5/2] bbaaa, [5/3] bbbba, [5/4] ababb, [5/5] bbbaa, [5/6] abaab
Length 6:[6/0] abbbbb, [6/1] bbbaaa, [6/2] bbbbba, [6/3] babbbb, [6/4] aabbbb, [6/5] ababbb, [6/6] bbbbaa
Length 7:[7/0] abbbbba, [7/1] bbbbaaa, [7/2] abbbbbb, [7/3] baabbbb, [7/4] bbbbbaa, [7/5] abaabbb, [7/6] bbabaaa

Considering [length 5 / frequency 0] abbbb=c.

Step 2

Rewriting system is complete. See a, b | abaabbbba=ab.