| Back: | ⟨a, b | abaabbaba=ba⟩ |
|---|
Solved by morph:3/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | abaabbba ⇒ baabbaba |
| 2. | abaabbaba ⇒ ba |
| 3. | abaabbbba ⇒ baabbabba |
| 4. | abaabbabba ⇒ bba |
| 5. | abaabbbbba ⇒ baabbabbba |
| 6. | abaabbabbba ⇒ bbba |
| 7. | abaabbbbbba ⇒ baabbabbbba |
| 8. | abaabbabbbba ⇒ bbbba |
| 9. | abaabbbbbbba ⇒ baabbabbbbba |
| 10. | abaabbabbbbba ⇒ bbbbba |
| 11. | abaabbbbbbbba ⇒ baabbabbbbbba |
| 12. | abaabbabbbbbba ⇒ bbbbbba |
| 13. | abaabbbbbbbbba ⇒ baabbabbbbbbba |
| 14. | abaabbabbbbbbba ⇒ bbbbbbba |
| 15. | abaabbbbbbbbbba ⇒ baabbabbbbbbbba |
| 16. | abaabbabbbbbbbba ⇒ bbbbbbbba |
| 17. | abaabbbbbbbbbbba ⇒ baabbabbbbbbbbba |
| 18. | abaabbabbbbbbbbba ⇒ bbbbbbbbba |
| 19. | abaabbabbbbbbbbbba ⇒ bbbbbbbbbba |
| 20. | abaabbabbbbbbbbbbba ⇒ bbbbbbbbbbba |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa |
|---|---|
| Length 3: | [3/0] bbb, [3/1] bba, [3/2] aba, [3/3] abb, [3/4] aab, [3/5] baa, [3/6] bab |
| Length 4: | [4/0] bbbb, [4/1] abaa, [4/2] bbba, [4/3] aabb, [4/4] baab, [4/5] abbb, [4/6] abba |
| Length 5: | [5/0] bbbbb, [5/1] abaab, [5/2] bbbba, [5/3] baabb, [5/4] abbbb, [5/5] abbab, [5/6] aabba |
| Length 6: | [6/0] bbbbbb, [6/1] abaabb, [6/2] bbbbba, [6/3] abbbbb, [6/4] aabbab, [6/5] baabba, [6/6] abbabb |
| Length 7: | [7/0] bbbbbbb, [7/1] bbbbbba, [7/2] abaabba, [7/3] abaabbb, [7/4] abbbbbb, [7/5] baabbab, [7/6] aabbabb |
Considering [length 3 / frequency 1] bba=c.
Rewriting system is complete. See ⟨a, b | abaabbaba=ba⟩.