Morphocompletion for #4277 ⟨a, b | abaabbaba=ba

Solved by morph:3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abaabbba ⇒ baabbaba
2. abaabbaba ⇒ ba
3. abaabbbba ⇒ baabbabba
4. abaabbabba ⇒ bba
5. abaabbbbba ⇒ baabbabbba
6. abaabbabbba ⇒ bbba
7. abaabbbbbba ⇒ baabbabbbba
8. abaabbabbbba ⇒ bbbba
9. abaabbbbbbba ⇒ baabbabbbbba
10. abaabbabbbbba ⇒ bbbbba
11. abaabbbbbbbba ⇒ baabbabbbbbba
12. abaabbabbbbbba ⇒ bbbbbba
13. abaabbbbbbbbba ⇒ baabbabbbbbbba
14. abaabbabbbbbbba ⇒ bbbbbbba
15. abaabbbbbbbbbba ⇒ baabbabbbbbbbba
16. abaabbabbbbbbbba ⇒ bbbbbbbba
17. abaabbbbbbbbbbba ⇒ baabbabbbbbbbbba
18. abaabbabbbbbbbbba ⇒ bbbbbbbbba
19. abaabbabbbbbbbbbba ⇒ bbbbbbbbbba
20. abaabbabbbbbbbbbbba ⇒ bbbbbbbbbbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:[3/0] bbb, [3/1] bba, [3/2] aba, [3/3] abb, [3/4] aab, [3/5] baa, [3/6] bab
Length 4:[4/0] bbbb, [4/1] abaa, [4/2] bbba, [4/3] aabb, [4/4] baab, [4/5] abbb, [4/6] abba
Length 5:[5/0] bbbbb, [5/1] abaab, [5/2] bbbba, [5/3] baabb, [5/4] abbbb, [5/5] abbab, [5/6] aabba
Length 6:[6/0] bbbbbb, [6/1] abaabb, [6/2] bbbbba, [6/3] abbbbb, [6/4] aabbab, [6/5] baabba, [6/6] abbabb
Length 7:[7/0] bbbbbbb, [7/1] bbbbbba, [7/2] abaabba, [7/3] abaabbb, [7/4] abbbbbb, [7/5] baabbab, [7/6] aabbabb

Considering [length 3 / frequency 1] bba=c.

Step 2

Rewriting system is complete. See a, b | abaabbaba=ba.