Morphocompletion for #4258 ⟨a, b | abaabaaab=ba

Solved by morph:7/3. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaabaaab ⇒ ba
2. abaaababa ⇒ baaaabaab
3. abaabaaba ⇒ baaabaaab
4. baaabaaba ⇒ ababaaaab
5. ababaaaba ⇒ baabaaaab
6. baabaaaabba ⇒ abbaaaabaab
7. baaabaaabaab ⇒ ababa
8. ababaaaabaab ⇒ baaba
9. baaaababaaaab ⇒ ababaa
10. baabaaaabaabaab ⇒ abaababa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] baa, [3/2] aab, [3/3] aaa, [3/4] bab, [3/5] bba, [3/6] abb
Length 4:[4/0] abaa, [4/1] aaba, [4/2] baab, [4/3] baaa, [4/4] aaab, [4/5] abab, [4/6] aaaa
Length 5:[5/0] abaab, [5/1] baaba, [5/2] aabaa, [5/3] abaaa, [5/4] aaaba, [5/5] baaab, [5/6] ababa
Length 6:[6/0] abaaba, [6/1] aabaab, [6/2] baaaba, [6/3] baabaa, [6/4] baaaab, [6/5] abaaab, [6/6] aaabaa
Length 7:[7/0] aaabaab, [7/1] baabaaa, [7/2] ababaaa, [7/3] baaabaa, [7/4] abaabaa, [7/5] abaaaba, [7/6] aabaaba

Considering [length 7 / frequency 3] baaabaa=c.

Step 2

Rewriting system is complete. See a, b | abaabaaab=ba.