Morphocompletion for #4254 ⟨a, b | abaaabbba=ba⟩

Back:⟨a, b | abaaabbba=ba⟩

Solved by morph:5/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abaaabbba ⇒ ba
2. abaaabbbba ⇒ bba
3. abaaabbbbba ⇒ bbba
4. abaaabbbbbba ⇒ bbbba
5. abaaabbbbbbba ⇒ bbbbba
6. abaaabbbbbbbba ⇒ bbbbbba
7. abaaabbbbbbbbba ⇒ bbbbbbba
8. abaaabbbbbbbbbba ⇒ bbbbbbbba
9. abaaabbbbbbbbbbba ⇒ bbbbbbbbba
10. abaaabbbbbbbbbbbba ⇒ bbbbbbbbbba
11. abaaabbbbbbbbbbbbba ⇒ bbbbbbbbbbba
12. abaaabbbbbbbbbbbbbba ⇒ bbbbbbbbbbbba
13. abaaabbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbba
14. abaaabbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbba
15. abaaabbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbba
16. abaaabbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbba
17. abaaabbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbba
18. abaaabbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbba
19. abaaabbbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbba
20. abaaabbbbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb230lf:230,rf:190,rp:19
[2/1]ab60lf:40,lp:20
[2/2]ba60lf:40,ls:20,rf:20,rp:1,rs:20,re:1,lsrp:1,lsrs:20
[2/3]aa40lf:40
[3/0]bbb210lf:210,rf:171,rp:18
[3/1]bba40lf:20,ls:20,rf:19,rp:1,rs:19,re:1,lsrp:1,lsrs:19
[3/2]aba40lf:20,lp:20
[3/3]abb20lf:20
[3/4]aab20lf:20
[3/5]baa20lf:20
[3/6]aaa20lf:20
[4/0]bbbb190lf:190,rf:153,rp:17,a:1
[4/1]bbba40lf:20,ls:20,rf:18,rp:1,rs:18,re:1,lsrp:1,lsrs:18
[4/2]abaa40lf:20,lp:20
[4/3]abbb20lf:20
[4/4]aabb20lf:20
[4/5]aaab20lf:20
[4/6]baaa20lf:20
[5/0]bbbbb171lf:171,rf:136,rp:16,a:2
[5/1]abaaa40lf:20,lp:20
[5/2]bbbba38lf:19,ls:19,rf:17,rp:1,rs:17,re:1,lsrp:1,lsrs:17,a:1
[5/3]aabbb20lf:20
[5/4]aaabb20lf:20
[5/5]baaab20lf:20
[5/6]abbbb19lf:19,a:1
[6/0]bbbbbb153lf:153,rf:120,rp:15,a:3
[6/1]abaaab40lf:20,lp:20
[6/2]bbbbba36lf:18,ls:18,rf:16,rp:1,rs:16,re:1,lsrp:1,lsrs:16,a:2
[6/3]aaabbb20lf:20
[6/4]baaabb20lf:20
[6/5]aabbbb19lf:19,a:1
[6/6]abbbbb18lf:18,a:2
[7/0]bbbbbbb136lf:136,rf:105,rp:14,a:4
[7/1]abaaabb40lf:20,lp:20
[7/2]bbbbbba34lf:17,ls:17,rf:15,rp:1,rs:15,re:1,lsrp:1,lsrs:15,a:3
[7/3]baaabbb20lf:20
[7/4]aaabbbb19lf:19,a:1
[7/5]aabbbbb18lf:18,a:2
[7/6]abbbbbb17lf:17,a:3

Considering [length 5 / frequency 2] bbbba=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaaabbba=ba⟩.