| Back: | ⟨a, b | abaaabbba=ab⟩ |
|---|
Solved by morph:4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | ababbb ⇒ abbbba |
| 2. | abaaabbb ⇒ abbbbaaa |
| 3. | abbbbbaaaa ⇒ abb |
| 4. | abbbbaaaab ⇒ abb |
| 5. | abbaabbbaa ⇒ abb |
| 6. | ababbbaaab ⇒ abb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 20 | lf:12,lp:6,ls:2,rf:6,rp:6,lprp:6,lsrp:2,a:4 |
|---|---|---|---|
| [2/1] | bb | 18 | lf:16,ls:2,rf:10,rs:4,a:4 |
| [2/2] | aa | 14 | lf:12,ls:2,rf:2,rs:1,a:4 |
| [2/3] | ba | 8 | lf:8,rf:2,rs:1,a:4 |
| [3/0] | bbb | 11 | lf:9,ls:2,rf:4,a:4 |
| [3/1] | abb | 10 | lf:7,lp:3,rf:6,rp:6,rs:4,re:4,lprp:3,lprs:3,a:4 |
| [3/2] | baa | 7 | lf:6,ls:1,rf:1,a:4 |
| [3/3] | aaa | 7 | lf:6,ls:1,rf:1,rs:1,a:4 |
| [3/4] | aab | 6 | lf:4,ls:2,a:4 |
| [3/5] | aba | 6 | lf:3,lp:3,a:4 |
| [3/6] | bba | 5 | lf:5,rf:2,rs:1,a:4 |
| [4/0] | abbb | 10 | lf:6,lp:2,ls:2,rf:2,rp:2,lsrp:2,a:4 |
| [4/1] | bbaa | 6 | lf:5,ls:1,rf:1,a:4 |
| [4/2] | aaab | 5 | lf:3,ls:2,a:4 |
| [4/3] | bbba | 4 | lf:4,rf:2,rs:1,a:4 |
| [4/4] | abab | 4 | lf:2,lp:2,a:20 |
| [4/5] | baaa | 4 | lf:4,rf:1,rs:1,a:4 |
| [4/6] | bbbb | 3 | lf:3,rf:2,a:4 |
| [5/0] | bbbaa | 5 | lf:4,ls:1,rf:1,a:4 |
| [5/1] | abbbb | 4 | lf:2,lp:2,rf:2,rp:2,a:4 |
| [5/2] | ababb | 4 | lf:2,lp:2,a:20 |
| [5/3] | babbb | 3 | lf:2,ls:1,a:20 |
| [5/4] | aabbb | 3 | lf:2,ls:1,a:4 |
| [5/5] | baaab | 3 | lf:2,ls:1,a:4 |
| [5/6] | bbaaa | 3 | lf:3,rf:1,rs:1,a:4 |
| [6/0] | abbbaa | 3 | lf:2,ls:1,a:14 |
| [6/1] | bbbaaa | 3 | lf:3,rf:1,rs:1,a:4 |
| [6/2] | bbaaaa | 3 | lf:2,ls:1,a:35 |
| [6/3] | abbbbb | 2 | lf:1,lp:1,a:41 |
| [6/4] | ababbb | 2 | lf:1,lp:1,a:20 |
| [6/5] | abbbba | 2 | lf:1,lp:1,rf:2,rp:2,rs:1,re:1,a:4 |
| [6/6] | bbbbaa | 2 | lf:2,rf:1,a:4 |
| [7/0] | bbbaaaa | 3 | lf:2,ls:1,a:35 |
| [7/1] | abbbbba | 2 | lf:1,lp:1,a:41 |
| [7/2] | ababbba | 2 | lf:1,lp:1,a:20 |
| [7/3] | abbaabb | 2 | lf:1,lp:1,a:14 |
| [7/4] | abbbbaa | 2 | lf:1,lp:1,rf:1,rp:1,a:4 |
| [7/5] | baaabbb | 2 | lf:1,ls:1,a:4 |
| [7/6] | bbbaaab | 2 | lf:1,ls:1,a:20 |
Considering [length 4 / frequency 0] abbb=c.
Rewriting system is complete. See ⟨a, b | abaaabbba=ab⟩.