Morphocompletion for #4250 ⟨a, b | abaaabbab=ba

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abaaabbab ⇒ ba
2. abaaabbba ⇒ baaaabbab
3. baaaabbabbaaabbab ⇒ abaaabbbba
4. abaaabbaabaaabbbba ⇒ baaaaabbabbaaabbab
5. baaaabbabbaaabbba ⇒ abaaabbbbaaaabbab
6. baaaaabbabbaaabbabbaaabbab ⇒ abaaabbaabaaabbbbba
7. abaaabbaabaaabbaabaaabbbbba ⇒ baaaaaabbabbaaabbabbaaabbab
8. baaaabbabbaaabbaabaaabbbba ⇒ abaaabbbbaaaaabbabbaaabbab
9. baaaaabbabbaaabbabbaaabbba ⇒ abaaabbaabaaabbbbbaaaabbab
10. baaaaaabbabbaaabbabbaaabbabbaaabbab ⇒ abaaabbaabaaabbaabaaabbbbbba
11. abaaabbaabaaabbaabaaabbaabaaabbbbbba ⇒ baaaaaaabbabbaaabbabbaaabbabbaaabbab
12. baaaabbabbaaabbaabaaabbaabaaabbbbba ⇒ abaaabbbbaaaaaabbabbaaabbabbaaabbab
13. baaaaabbabbaaabbabbaaabbaabaaabbbba ⇒ abaaabbaabaaabbbbbaaaaabbabbaaabbab
14. baaaaaabbabbaaabbabbaaabbabbaaabbba ⇒ abaaabbaabaaabbaabaaabbbbbbaaaabbab
15. baaaaaaabbabbaaabbabbaaabbabbaaabbabbaaabbab ⇒ abaaabbaabaaabbaabaaabbaabaaabbbbbbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] bba, [3/1] abb, [3/2] baa, [3/3] aaa, [3/4] aab, [3/5] bab, [3/6] bbb
Length 4:[4/0] abba, [4/1] baaa, [4/2] aabb, [4/3] aaab, [4/4] bbab, [4/5] bbaa, [4/6] bbba
Length 5:[5/0] aaabb, [5/1] aabba, [5/2] baaab, [5/3] abbab, [5/4] abbaa, [5/5] bbabb, [5/6] babba
Length 6:[6/0] baaabb, [6/1] aaabba, [6/2] aabbab, [6/3] bbabba, [6/4] abbabb, [6/5] babbaa, [6/6] bbaaab
Length 7:[7/0] aaabbab, [7/1] baaabba, [7/2] bbabbaa, [7/3] abbabba, [7/4] bbaaabb, [7/5] aabbabb, [7/6] babbaaa

Considering [length 3 / frequency 0] bba=c.

Step 2

Rewriting system is complete. See a, b | abaaabbab=ba.