Morphocompletion for #4242 ⟨a, b | abaaabaab=ba

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abaaabaab ⇒ ba
2. abaaababa ⇒ baaaabaab
3. baaaabaabaabaab ⇒ abaaabba
4. abaaabaaabaaabba ⇒ baaaaabaabaabaab
5. baaaabaabaababa ⇒ abaaabbaaaabaab
6. baaaabaabbaaabaab ⇒ abaaababba
7. abaaabaaabaaababba ⇒ baaaaabaabbaaabaab
8. baaaabaabbaaababa ⇒ abaaababbaaaabaab
9. baaaabaabaabaaabaaabba ⇒ abaaabbaaaaabaabaabaab
10. baaaaabaabaabaabbaaabaab ⇒ abaaabaaabaaabbba
11. abaaabaaabaaabaaabaaabbba ⇒ baaaaaabaabaabaabbaaabaab
12. baaaabaabaabaaabaaababba ⇒ abaaabbaaaaabaabbaaabaab
13. baaaabaabbaaabaaabaaabba ⇒ abaaababbaaaaabaabaabaab
14. baaaaabaabaabaabbaaababa ⇒ abaaabaaabaaabbbaaaabaab
15. baaaaabaabbaaabaabbaaabaab ⇒ abaaabaaabaaababbba
16. abaaabaaabaaabaaabaaababbba ⇒ baaaaaabaabbaaabaabbaaabaab
17. baaaabaabbaaabaaabaaababba ⇒ abaaababbaaaaabaabbaaabaab
18. baaaaabaabbaaabaabbaaababa ⇒ abaaabaaabaaababbbaaaabaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] baa, [3/1] aab, [3/2] aba, [3/3] aaa, [3/4] bba, [3/5] abb, [3/6] bab
Length 4:[4/0] baaa, [4/1] abaa, [4/2] aaba, [4/3] aaab, [4/4] baab, [4/5] abba, [4/6] aaaa
Length 5:[5/0] aabaa, [5/1] aaaba, [5/2] baaab, [5/3] abaab, [5/4] abaaa, [5/5] baaaa, [5/6] aabba
Length 6:[6/0] aaabaa, [6/1] baaaba, [6/2] abaaab, [6/3] aabaab, [6/4] aabaaa, [6/5] baaaab, [6/6] abaaba
Length 7:[7/0] abaaaba, [7/1] baaabaa, [7/2] aaabaab, [7/3] aabaaab, [7/4] aaabaaa, [7/5] baaaaba, [7/6] aabaaba

Considering [length 3 / frequency 0] baa=c.

Step 2

Rewriting system is complete. See a, b | abaaabaab=ba.