Morphocompletion for #4237 ⟨a, b | abaaaabba=ab⟩

Back:⟨a, b | abaaaabba=ab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababb ⇒ abbba
2. abaaabbaa ⇒ ab
3. abaaaabb ⇒ abaaabba
4. abaaaabba ⇒ ab
5. abbabb ⇒ abbbba
6. abbaaabbaa ⇒ abb
7. abbaaaabba ⇒ abb
8. ababbaaaab ⇒ abb
9. abbbaaaabba ⇒ abbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] aa, [2/2] ba, [2/3] bb
Length 3:[3/0] abb, [3/1] bba, [3/2] aaa, [3/3] baa, [3/4] aba, [3/5] aab, [3/6] bab
Length 4:[4/0] abba, [4/1] bbaa, [4/2] aaab, [4/3] aabb, [4/4] baaa, [4/5] abaa, [4/6] babb
Length 5:[5/0] abbaa, [5/1] aabba, [5/2] aaabb, [5/3] aaaab, [5/4] abaaa, [5/5] baaaa, [5/6] bbaaa
Length 6:[6/0] aaabba, [6/1] baaaab, [6/2] aaaabb, [6/3] abbaaa, [6/4] aabbaa, [6/5] abaaaa, [6/6] bbaaaa
Length 7:[7/0] aaaabba, [7/1] baaaabb, [7/2] bbaaaab, [7/3] aaabbaa, [7/4] abaaaab, [7/5] abbaaaa, [7/6] abaaabb

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaaaabba=ab⟩.