| Back: | ⟨a, b | abaaaabba=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | ababb ⇒ abbba |
| 2. | abaaabbaa ⇒ ab |
| 3. | abaaaabb ⇒ abaaabba |
| 4. | abaaaabba ⇒ ab |
| 5. | abbabb ⇒ abbbba |
| 6. | abbaaabbaa ⇒ abb |
| 7. | abbaaaabba ⇒ abb |
| 8. | ababbaaaab ⇒ abb |
| 9. | abbbaaaabba ⇒ abbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 29 | lf:19,lp:9,ls:1,rf:10,rp:9,rs:2,re:2,lprp:9,lsrp:1,lprs:2 |
|---|---|---|---|
| [2/1] | aa | 23 | lf:21,ls:2,rf:2 |
| [2/2] | ba | 18 | lf:15,ls:3,rf:4,rs:3 |
| [2/3] | bb | 17 | lf:14,ls:3,rf:11,rs:4 |
| [3/0] | abb | 20 | lf:13,lp:4,ls:3,rf:7,rp:6,rs:3,re:3,lprp:4,lsrp:2,lprs:2 |
| [3/1] | bba | 13 | lf:10,ls:3,rf:3,rs:3 |
| [3/2] | aaa | 12 | lf:12,rf:1 |
| [3/3] | baa | 11 | lf:9,ls:2,rf:1 |
| [3/4] | aba | 10 | lf:5,lp:5,rf:1,rp:1,lprp:1 |
| [3/5] | aab | 8 | lf:7,ls:1,rf:1 |
| [3/6] | bab | 3 | lf:3,a:21 |
| [4/0] | abba | 15 | lf:9,lp:3,ls:3,rf:1,rs:1 |
| [4/1] | bbaa | 8 | lf:6,ls:2,a:1 |
| [4/2] | aaab | 8 | lf:7,ls:1,rf:1 |
| [4/3] | aabb | 7 | lf:6,ls:1,rf:1 |
| [4/4] | baaa | 7 | lf:7,rf:1 |
| [4/5] | abaa | 6 | lf:3,lp:3,rf:1,rp:1,lprp:1 |
| [4/6] | babb | 5 | lf:3,ls:2,a:21 |
| [5/0] | abbaa | 9 | lf:5,lp:2,ls:2,a:1 |
| [5/1] | aabba | 8 | lf:5,ls:3,rf:1,rs:1 |
| [5/2] | aaabb | 7 | lf:6,ls:1,rf:1 |
| [5/3] | aaaab | 6 | lf:5,ls:1 |
| [5/4] | abaaa | 6 | lf:3,lp:3,rf:1,rp:1,lprp:1 |
| [5/5] | baaaa | 5 | lf:5 |
| [5/6] | bbaaa | 4 | lf:4,a:1 |
| [6/0] | aaabba | 8 | lf:5,ls:3,rf:1,rs:1 |
| [6/1] | baaaab | 6 | lf:5,ls:1 |
| [6/2] | aaaabb | 5 | lf:4,ls:1 |
| [6/3] | abbaaa | 5 | lf:3,lp:2,a:1 |
| [6/4] | aabbaa | 4 | lf:2,ls:2,a:12 |
| [6/5] | abaaaa | 4 | lf:2,lp:2 |
| [6/6] | bbaaaa | 3 | lf:3,a:1 |
| [7/0] | aaaabba | 6 | lf:3,ls:3 |
| [7/1] | baaaabb | 5 | lf:4,ls:1 |
| [7/2] | bbaaaab | 4 | lf:3,ls:1,a:1 |
| [7/3] | aaabbaa | 4 | lf:2,ls:2,a:12 |
| [7/4] | abaaaab | 4 | lf:2,lp:2 |
| [7/5] | abbaaaa | 3 | lf:2,lp:1,a:1 |
| [7/6] | abaaabb | 2 | lf:1,lp:1,rf:1,rp:1,a:2 |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | abaaaabba=ab⟩.