Morphocompletion for #4222 ⟨a, b | aabbbbbba=ab⟩

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#	Rule
1.	aabbbbbba ⇒ ab
2.	ababbbbbba ⇒ abb
3.	aabbbbbbb ⇒ abbbbbbba
4.	abbabbbbbba ⇒ abbb
5.	ababbbbbbb ⇒ abbbbbbbba
6.	abbbabbbbbba ⇒ abbbb
7.	abbabbbbbbb ⇒ abbbbbbbbba
8.	abbbbabbbbbba ⇒ abbbbb
9.	abbbabbbbbbb ⇒ abbbbbbbbbba
10.	abbbbbabbbbbba ⇒ abbbbbb
11.	abbbbabbbbbbb ⇒ abbbbbbbbbbba
12.	abbbbbbabbbbbba ⇒ abbbbbbb
13.	abbbbbabbbbbbb ⇒ abbbbbbbbbbbba
14.	abbbbbbbabbbbbba ⇒ abbbbbbbb
15.	abbbbbbabbbbbbb ⇒ abbbbbbbbbbbbba
16.	abbbbbbbbabbbbbba ⇒ abbbbbbbbb
17.	abbbbbbbabbbbbbb ⇒ abbbbbbbbbbbbbba
18.	abbbbbbbbbabbbbbba ⇒ abbbbbbbbbb
19.	abbbbbbbbbbabbbbbba ⇒ abbbbbbbbbbb
20.	abbbbbbbbbbbabbbbbba ⇒ abbbbbbbbbbbb
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:	[3/0] bbb, [3/1] abb, [3/2] bba, [3/3] bab, [3/4] aab, [3/5] aba
Length 4:	[4/0] bbbb, [4/1] abbb, [4/2] bbba, [4/3] babb, [4/4] bbab, [4/5] aabb, [4/6] abab
Length 5:	[5/0] bbbbb, [5/1] abbbb, [5/2] bbbba, [5/3] babbb, [5/4] bbabb, [5/5] bbbab, [5/6] aabbb
Length 6:	[6/0] bbbbbb, [6/1] abbbbb, [6/2] bbbbba, [6/3] babbbb, [6/4] bbabbb, [6/5] bbbabb, [6/6] bbbbab
Length 7:	[7/0] abbbbbb, [7/1] bbbbbbb, [7/2] bbbbbba, [7/3] babbbbb, [7/4] bbabbbb, [7/5] bbbabbb, [7/6] bbbbabb

Considering [length 7 / frequency 0] abbbbbb=c.

Reduction order:
- Left-to-right recursive path with deg(a) = deg(c) = 0, a < c; deg(b) = 1
Auxiliary generators:
1. abbbbbb=c

Rewriting system is complete. See ⟨a, b | aabbbbbba=ab⟩.