Morphocompletion for #4215 ⟨a, b | aabbbbbaa=ab⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbbbbab ⇒ abbbbbbaa
2. aabbbbbaa ⇒ ab
3. ababbbbbab ⇒ abbbbbbbaa
4. ababbbbbaa ⇒ abb
5. abbabbbbbab ⇒ abbbbbbbbaa
6. abbabbbbbaa ⇒ abbb
7. abbbabbbbbab ⇒ abbbbbbbbbaa
8. abbbabbbbbaa ⇒ abbbb
9. abbbbabbbbbab ⇒ abbbbbbbbbbaa
10. abbbbabbbbbaa ⇒ abbbbb
11. abbbbbabbbbbab ⇒ abbbbbbbbbbbaa
12. abbbbbabbbbbaa ⇒ abbbbbb
13. abbbbbbabbbbbaa ⇒ abbbbbbb
14. abbbbbbaabbbbaa ⇒ aabbbbbb
15. abbbbbbbabbbbbaa ⇒ abbbbbbbb
16. abbbbbbbaabbbbaa ⇒ ababbbbbb
17. abbbbbbbbabbbbbaa ⇒ abbbbbbbbb
18. abbbbbbbbaabbbbaa ⇒ abbabbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb125lf:125,rf:97,rs:11
[2/1]ab62lf:40,lp:16,ls:6,rf:20,rp:17,rs:1,re:1,lprp:15,lsrp:6
[2/2]ba34lf:34,rf:8
[2/3]aa31lf:17,lp:2,ls:12,rf:7,rp:1,rs:6,lsrp:1,lprs:1
[3/0]bbb93lf:93,rf:79,rs:10
[3/1]abb46lf:32,lp:14,rf:18,rp:15,rs:1,re:1,lprp:12
[3/2]bba32lf:32,rf:7
[3/3]baa27lf:15,ls:12,rf:6,rs:6
[3/4]bab25lf:19,ls:6,rf:2,a:1
[3/5]aab7lf:5,lp:2,rf:1,rp:1
[3/6]aba4lf:2,lp:2,rf:1,rp:1,a:2
[4/0]bbbb63lf:63,rf:63,rs:9
[4/1]abbb42lf:30,lp:12,rf:16,rp:13,rs:1,re:1,lprp:9
[4/2]bbba30lf:30,rf:6
[4/3]bbaa27lf:15,ls:12,rf:6,rs:6
[4/4]bbab23lf:17,ls:6,rf:1,a:1
[4/5]babb13lf:13,rf:2,a:2
[4/6]aabb7lf:5,lp:2,rf:1,rp:1
[5/0]abbbb38lf:28,lp:10,rf:15,rp:12,rs:1,re:1,lprp:7
[5/1]bbbbb35lf:35,rf:48,rs:8
[5/2]bbbba28lf:28,rf:6
[5/3]bbbaa27lf:15,ls:12,rf:6,rs:6
[5/4]bbbab21lf:15,ls:6,a:1
[5/5]babbb13lf:13,rf:2,a:2
[5/6]bbabb11lf:11,rf:1,a:3
[6/0]abbbbb31lf:23,lp:8,rf:14,rp:11,rs:1,re:1,lprp:5
[6/1]bbbbaa27lf:15,ls:12,rf:6,rs:6
[6/2]bbbbba23lf:23,rf:6
[6/3]bbbbab19lf:13,ls:6,a:1
[6/4]babbbb13lf:13,rf:2,a:2
[6/5]bbbbbb12lf:12,rf:34,rs:7,a:1
[6/6]bbabbb11lf:11,rf:1,a:3
[7/0]bbbbbaa21lf:12,ls:9,rf:6,rs:6
[7/1]abbbbba19lf:17,lp:2
[7/2]bbbbbab17lf:11,ls:6,a:1
[7/3]babbbbb13lf:13,rf:2,a:2
[7/4]abbbbbb12lf:6,lp:6,rf:13,rp:10,rs:4,re:1,lprp:3,lprs:3,a:1
[7/5]bbabbbb11lf:11,rf:1,a:3
[7/6]bbbabbb9lf:9,a:5

Considering [length 5 / frequency 0] abbbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbbbbaa=ab⟩.