Morphocompletion for #4203 ⟨a, b | aabbbabba=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbbabba ⇒ ab
2. ababbbabba ⇒ abb
3. aabbbabbb ⇒ abbbbabba
4. abbabbbabba ⇒ abbb
5. ababbbabbb ⇒ abbbbbabba
6. abbbbabbaabba ⇒ aabbbb
7. abbbabbbabba ⇒ abbbb
8. abbabbbabbb ⇒ abbbbbbabba
9. abbbbbabbaabba ⇒ ababbbb
10. abbbbabbbabba ⇒ abbbbb
11. abbbabbbabbb ⇒ abbbbbbbabba
12. abbbbbbabbaabba ⇒ abbabbbb
13. abbbbbabbbabba ⇒ abbbbbb
14. abbbbbbbabbaabba ⇒ abbbabbbb
15. abbbbbbabbbabba ⇒ abbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb85lf:81,ls:4,rf:58,rs:10
[2/1]ab56lf:43,lp:13,rf:22,rp:14,rs:1,re:1,lprp:12
[2/2]ba50lf:39,ls:11,rf:11,rs:4
[2/3]aa8lf:6,lp:2,rf:1,rp:1
[3/0]abb52lf:41,lp:11,rf:20,rp:12,rs:1,re:1,lprp:9
[3/1]bba48lf:37,ls:11,rf:10,rs:4
[3/2]bbb44lf:40,ls:4,rf:38,rs:9
[3/3]bab24lf:24,rf:7
[3/4]aab8lf:6,lp:2,rf:1,rp:1
[3/5]aba4lf:2,lp:2,rf:1,rp:1,a:1
[3/6]baa4lf:4,a:13
[4/0]abbb37lf:24,lp:9,ls:4,rf:14,rp:10,rs:1,re:1,lprp:6,lsrp:4
[4/1]abba30lf:17,lp:2,ls:11,rf:5,rp:1,rs:4,lsrp:1,lprs:1
[4/2]babb24lf:24,rf:7
[4/3]bbab22lf:22,rf:6
[4/4]bbba20lf:20,rf:5
[4/5]bbbb16lf:16,rf:24,rs:8,a:3
[4/6]aabb8lf:6,lp:2,rf:1,rp:1
[5/0]bbabb22lf:22,rf:6
[5/1]bbbab20lf:20,rf:5
[5/2]babba18lf:11,ls:7,rf:4,rs:4
[5/3]babbb17lf:13,ls:4,rf:3,a:1
[5/4]abbba15lf:13,lp:2,rf:1,rp:1
[5/5]abbbb14lf:7,lp:7,rf:12,rp:8,rs:5,re:1,lprp:3,lprs:4,a:3
[5/6]bbbbb9lf:9,rf:12,rs:3,a:5
[6/0]bbbabb20lf:20,rf:5
[6/1]bbabba18lf:11,ls:7,rf:4,rs:4
[6/2]bbabbb15lf:11,ls:4,rf:2,a:2
[6/3]abbbab15lf:13,lp:2,rf:1,rp:1
[6/4]abbbbb10lf:5,lp:5,rf:6,rp:6,rs:1,re:1,lprp:2,a:5
[6/5]babbba9lf:9,a:1
[6/6]baabba8lf:4,ls:4,a:13
[7/0]bbbabba18lf:11,ls:7,rf:4,rs:4
[7/1]abbbabb15lf:13,lp:2,rf:1,rp:1
[7/2]bbbabbb13lf:9,ls:4,rf:1,a:3
[7/3]babbbab9lf:9,a:1
[7/4]bbaabba8lf:4,ls:4,a:13
[7/5]bbbbabb7lf:7,rf:4,a:4
[7/6]bbabbba7lf:7,a:2

Considering [length 4 / frequency 0] abbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbbabba=ab⟩.