Morphocompletion for #4203 ⟨a, b | aabbbabba=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#	Rule
1.	aabbbabba ⇒ ab
2.	ababbbabba ⇒ abb
3.	aabbbabbb ⇒ abbbbabba
4.	abbabbbabba ⇒ abbb
5.	ababbbabbb ⇒ abbbbbabba
6.	abbbbabbaabba ⇒ aabbbb
7.	abbbabbbabba ⇒ abbbb
8.	abbabbbabbb ⇒ abbbbbbabba
9.	abbbbbabbaabba ⇒ ababbbb
10.	abbbbabbbabba ⇒ abbbbb
11.	abbbabbbabbb ⇒ abbbbbbbabba
12.	abbbbbbabbaabba ⇒ abbabbbb
13.	abbbbbabbbabba ⇒ abbbbbb
14.	abbbbbbbabbaabba ⇒ abbbabbbb
15.	abbbbbbabbbabba ⇒ abbbbbbb
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:	[3/0] abb, [3/1] bba, [3/2] bbb, [3/3] bab, [3/4] aab, [3/5] aba, [3/6] baa
Length 4:	[4/0] abbb, [4/1] abba, [4/2] babb, [4/3] bbab, [4/4] bbba, [4/5] bbbb, [4/6] aabb
Length 5:	[5/0] bbabb, [5/1] bbbab, [5/2] babba, [5/3] babbb, [5/4] abbba, [5/5] abbbb, [5/6] bbbbb
Length 6:	[6/0] bbbabb, [6/1] bbabba, [6/2] bbabbb, [6/3] abbbab, [6/4] abbbbb, [6/5] babbba, [6/6] baabba
Length 7:	[7/0] bbbabba, [7/1] abbbabb, [7/2] bbbabbb, [7/3] babbbab, [7/4] bbaabba, [7/5] bbbbabb, [7/6] bbabbba

Considering [length 4 / frequency 0] abbb=c.

Reduction order:
- Left-to-right recursive path with deg(a) = deg(c) = 0, a < c; deg(b) = 1
Auxiliary generators:
1. abbb=c

Rewriting system is complete. See ⟨a, b | aabbbabba=ab⟩.