Morphocompletion for #4196 ⟨a, b | aabbbaaba=ba

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbbba ⇒ ba
2. bbbaaba ⇒ aabbbba
3. aaaabbbbba ⇒ bba
4. aaaabaabbbba ⇒ baaba
5. bbbaabba ⇒ aabbbbba
6. aaaabbbbbba ⇒ bbba
7. bbbaabbba ⇒ aabbbbbba
8. aaaabbbbbbba ⇒ bbbba
9. aaaabbbbbbbba ⇒ bbbbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] aa, [2/2] ba, [2/3] ab
Length 3:[3/0] bbb, [3/1] bba, [3/2] aaa, [3/3] aab, [3/4] abb, [3/5] baa, [3/6] aba
Length 4:[4/0] bbba, [4/1] bbbb, [4/2] aaaa, [4/3] aabb, [4/4] abbb, [4/5] aaab, [4/6] baab
Length 5:[5/0] bbbba, [5/1] aaaab, [5/2] bbbbb, [5/3] aabbb, [5/4] abbbb, [5/5] bbbaa, [5/6] aaabb
Length 6:[6/0] aaaabb, [6/1] bbbbba, [6/2] bbbbbb, [6/3] bbbaab, [6/4] aabbbb, [6/5] aaabbb, [6/6] abbbbb
Length 7:[7/0] aaaabbb, [7/1] bbbbbba, [7/2] aaabbbb, [7/3] bbbaabb, [7/4] aabbbbb, [7/5] aabbbba, [7/6] bbbbbbb

Considering [length 4 / frequency 0] bbba=c.

Step 2

Rewriting system is complete. See a, b | aabbbaaba=ba.