Morphocompletion for #4195 ⟨a, b | aabbbaaba=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbbaaba ⇒ ab
2. ababbbaaba ⇒ abb
3. aabbbaabb ⇒ abbbbaaba
4. abbabbbaaba ⇒ abbb
5. ababbbaabb ⇒ abbbbbaaba
6. abbbbaababaaba ⇒ aabbbab
7. abbbabbbaaba ⇒ abbbb
8. abbabbbaabb ⇒ abbbbbbaaba
9. abbbbbaababaaba ⇒ ababbbab
10. abbbbabbbaaba ⇒ abbbbb
11. abbbabbbaabb ⇒ abbbbbbbaaba
12. abbbbbbaababaaba ⇒ abbabbbab
13. abbbbbabbbaaba ⇒ abbbbbb
14. abbbbabbbaabb ⇒ abbbbbbbbaaba
15. abbbbbbabbbaaba ⇒ abbbbbbb
16. abbbbbbbabbbaaba ⇒ abbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb75lf:70,ls:5,rf:60,rs:7
[2/1]ab63lf:49,lp:14,rf:26,rp:15,rs:4,re:1,lprp:13,lprs:3
[2/2]ba55lf:44,ls:11,rf:15,rs:5
[2/3]aa23lf:21,lp:2,rf:6,rp:1
[3/0]abb47lf:30,lp:12,ls:5,rf:16,rp:13,rs:1,re:1,lprp:10,lsrp:5
[3/1]bbb40lf:40,rf:44,rs:6
[3/2]aba32lf:19,lp:2,ls:11,rf:6,rp:1,rs:5,lsrp:1,lprs:1
[3/3]bba25lf:25,rf:9
[3/4]aab23lf:21,lp:2,rf:6,rp:1
[3/5]baa19lf:19,rf:5
[3/6]bab14lf:14,rf:5,rs:3,a:1
[4/0]abbb33lf:23,lp:10,rf:14,rp:11,rs:1,re:1,lprp:7
[4/1]aaba25lf:14,ls:11,rf:5,rs:5
[4/2]bbba23lf:23,rf:8
[4/3]baab19lf:19,rf:5
[4/4]bbbb17lf:17,rf:30,rs:5,a:2
[4/5]bbaa16lf:16,rf:5
[4/6]aabb14lf:7,lp:2,ls:5,rf:1,rp:1
[5/0]baaba25lf:14,ls:11,rf:5,rs:5
[5/1]abbba17lf:15,lp:2,rf:3
[5/2]abbbb16lf:8,lp:8,rf:10,rp:10,rs:1,re:1,lprp:5,a:2
[5/3]bbaab16lf:16,rf:5
[5/4]bbbaa16lf:16,rf:5
[5/5]babbb11lf:11,rf:2,a:1
[5/6]baabb10lf:5,ls:5,a:2
[6/0]bbaaba19lf:11,ls:8,rf:5,rs:5
[6/1]bbbaab16lf:16,rf:5
[6/2]abbbaa13lf:13
[6/3]babbba11lf:11,rf:2,a:1
[6/4]abbbbb10lf:5,lp:5,rf:8,rp:8,rs:1,re:1,lprp:3,a:4
[6/5]bbaabb10lf:5,ls:5,a:2
[6/6]bbabbb9lf:9,rf:1,a:3
[7/0]bbbaaba19lf:11,ls:8,rf:5,rs:5
[7/1]abbbaab13lf:13
[7/2]babbbaa11lf:11,a:1
[7/3]bbbaabb10lf:5,ls:5,a:2
[7/4]bbabbba9lf:9,rf:1,a:3
[7/5]bbbabbb7lf:7,a:5
[7/6]abbbbbb6lf:3,lp:3,rf:6,rp:6,rs:1,re:1,lprp:2,a:7

Considering [length 4 / frequency 0] abbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbbaaba=ab⟩.