Morphocompletion for #4187 ⟨a, b | aabbabbba=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbabbba ⇒ ab
2. abbbabbba ⇒ aabbabbbb
3. ababbabbba ⇒ abb
4. abbbbabbba ⇒ ababbabbbb
5. abbabbabbba ⇒ abbb
6. abbbbbabbba ⇒ abbabbabbbb
7. abbbabbabbba ⇒ abbbb
8. abbbbbbabbba ⇒ abbbabbabbbb
9. aabbaabbabbbb ⇒ abbbba
10. abbbbabbabbba ⇒ abbbbb
11. ababbaabbabbbb ⇒ abbbbba
12. abbbbbabbabbba ⇒ abbbbbb
13. abbabbaabbabbbb ⇒ abbbbbba
14. abbbbbbabbabbba ⇒ abbbbbbb
15. abbbabbaabbabbbb ⇒ abbbbbbba
16. abbbbbbbabbabbba ⇒ abbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb94lf:90,ls:4,rf:65,rs:11
[2/1]ab60lf:46,lp:14,rf:23,rp:15,rs:1,re:1,lprp:13
[2/2]ba54lf:42,ls:12,rf:11,rs:4
[2/3]aa8lf:6,lp:2,rf:1,rp:1
[3/0]abb56lf:44,lp:12,rf:21,rp:13,rs:1,re:1,lprp:10
[3/1]bba52lf:40,ls:12,rf:10,rs:4
[3/2]bbb50lf:46,ls:4,rf:44,rs:10
[3/3]bab26lf:26,rf:7
[3/4]aab8lf:6,lp:2,rf:1,rp:1
[3/5]baa4lf:4,a:12
[3/6]aba4lf:2,lp:2,rf:1,rp:1,a:1
[4/0]abbb36lf:26,lp:10,rf:15,rp:11,rs:1,re:1,lprp:7
[4/1]bbba34lf:22,ls:12,rf:5,rs:4
[4/2]babb26lf:26,rf:7
[4/3]bbbb24lf:20,ls:4,rf:29,rs:9,a:3
[4/4]bbab24lf:24,rf:6
[4/5]abba20lf:18,lp:2,rf:5,rp:1
[4/6]aabb8lf:6,lp:2,rf:1,rp:1
[5/0]abbba30lf:15,lp:3,ls:12,rf:1,rp:1,lsrp:1
[5/1]bbabb24lf:24,rf:6
[5/2]abbbb22lf:11,lp:7,ls:4,rf:13,rp:9,rs:5,re:1,lprp:4,lsrp:4,lprs:3,a:3
[5/3]babbb16lf:16,rf:4
[5/4]abbab16lf:14,lp:2,rf:5,rp:1
[5/5]bbbab10lf:10,rf:1,a:3
[5/6]babba10lf:10,rf:3,a:1
[6/0]babbba24lf:12,ls:12
[6/1]bbabbb16lf:16,rf:4
[6/2]abbabb16lf:14,lp:2,rf:5,rp:1
[6/3]bbbabb10lf:10,rf:1,a:3
[6/4]abbbbb10lf:5,lp:5,rf:7,rp:7,rs:1,re:1,lprp:3,a:4
[6/5]bbabba8lf:8,rf:2,a:2
[6/6]babbbb8lf:4,ls:4,rf:4,rs:4,a:6
[7/0]bbabbba24lf:12,ls:12
[7/1]abbabbb12lf:12,rf:4
[7/2]bbabbbb8lf:4,ls:4,rf:4,rs:4,a:6
[7/3]bbbbabb7lf:7,a:4
[7/4]babbabb7lf:7,rf:3,a:1
[7/5]bbbabba6lf:6,rf:1,a:3
[7/6]bbabbab6lf:6,rf:2,a:2

Considering [length 4 / frequency 0] abbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbabbba=ab⟩.