Morphocompletion for #4180 ⟨a, b | aabbabbaa=ab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbabbaa ⇒ ab
2. ababbabbaa ⇒ abb
3. aabbabbab ⇒ abbbabbaa
4. abbbabbaabaa ⇒ aabbb
5. abbabbabbaa ⇒ abbb
6. ababbabbab ⇒ abbbbabbaa
7. abbbbabbaabaa ⇒ ababbb
8. abbbabbabbaa ⇒ abbbb
9. abbabbabbab ⇒ abbbbbabbaa
10. abbbbbabbaabaa ⇒ abbabbb
11. abbbbabbabbaa ⇒ abbbbb
12. abbbabbaababbaa ⇒ aabbabbb
13. abbbbbbabbaabaa ⇒ abbbabbb
14. abbbbbabbabbaa ⇒ abbbbbb
15. abbbbbbabbabbaa ⇒ abbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] bb, [2/2] ba, [2/3] aa
Length 3:[3/0] abb, [3/1] bba, [3/2] bab, [3/3] baa, [3/4] bbb, [3/5] aab, [3/6] aba
Length 4:[4/0] abba, [4/1] bbab, [4/2] babb, [4/3] bbaa, [4/4] abbb, [4/5] bbbb, [4/6] bbba
Length 5:[5/0] babba, [5/1] bbabb, [5/2] abbaa, [5/3] abbab, [5/4] abbbb, [5/5] bbbab, [5/6] aabaa
Length 6:[6/0] bbabba, [6/1] babbaa, [6/2] abbabb, [6/3] babbab, [6/4] bbbabb, [6/5] abbbbb, [6/6] baabaa
Length 7:[7/0] bbabbaa, [7/1] abbabba, [7/2] bbabbab, [7/3] bbbabba, [7/4] babbabb, [7/5] bbaabaa, [7/6] bbbbabb

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See a, b | aabbabbaa=ab.