| Back: | ⟨a, b | aabbabbaa=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabbabbaa ⇒ ab |
| 2. | ababbabbaa ⇒ abb |
| 3. | aabbabbab ⇒ abbbabbaa |
| 4. | abbbabbaabaa ⇒ aabbb |
| 5. | abbabbabbaa ⇒ abbb |
| 6. | ababbabbab ⇒ abbbbabbaa |
| 7. | abbbbabbaabaa ⇒ ababbb |
| 8. | abbbabbabbaa ⇒ abbbb |
| 9. | abbabbabbab ⇒ abbbbbabbaa |
| 10. | abbbbbabbaabaa ⇒ abbabbb |
| 11. | abbbbabbabbaa ⇒ abbbbb |
| 12. | abbbabbaababbaa ⇒ aabbabbb |
| 13. | abbbbbbabbaabaa ⇒ abbbabbb |
| 14. | abbbbbabbabbaa ⇒ abbbbbb |
| 15. | abbbbbbabbabbaa ⇒ abbbbbbb |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] ab, [2/1] bb, [2/2] ba, [2/3] aa |
|---|---|
| Length 3: | [3/0] abb, [3/1] bba, [3/2] bab, [3/3] baa, [3/4] bbb, [3/5] aab, [3/6] aba |
| Length 4: | [4/0] abba, [4/1] bbab, [4/2] babb, [4/3] bbaa, [4/4] abbb, [4/5] bbbb, [4/6] bbba |
| Length 5: | [5/0] babba, [5/1] bbabb, [5/2] abbaa, [5/3] abbab, [5/4] abbbb, [5/5] bbbab, [5/6] aabaa |
| Length 6: | [6/0] bbabba, [6/1] babbaa, [6/2] abbabb, [6/3] babbab, [6/4] bbbabb, [6/5] abbbbb, [6/6] baabaa |
| Length 7: | [7/0] bbabbaa, [7/1] abbabba, [7/2] bbabbab, [7/3] bbbabba, [7/4] babbabb, [7/5] bbaabaa, [7/6] bbbbabb |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | aabbabbaa=ab⟩.