Morphocompletion for #4176 ⟨a, b | aabbababa=ab⟩

Solved by morph:3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbababa ⇒ ab
2. ababbababa ⇒ abb
3. aabbababb ⇒ abbbababa
4. abbabbababa ⇒ abbb
5. ababbababb ⇒ abbbbababa
6. abbbabbababa ⇒ abbbb
7. abbbababaababa ⇒ aabbabb
8. abbabbababb ⇒ abbbbbababa
9. abbbbabbababa ⇒ abbbbb
10. abbbbababaababa ⇒ ababbabb
11. abbbabbababb ⇒ abbbbbbababa
12. abbbbbabbababa ⇒ abbbbbb
13. abbbbbababaababa ⇒ abbabbabb
14. abbbbabbababb ⇒ abbbbbbbababa
15. abbbbbbabbababa ⇒ abbbbbbb
16. abbbbbbbabbababa ⇒ abbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]ab79lf:65,lp:14,rf:31,rp:15,rs:1,re:1,lprp:13
[2/1]ba71lf:60,ls:11,rf:20,rs:5
[2/2]bb59lf:54,ls:5,rf:55,rs:10
[2/3]aa7lf:5,lp:2,rf:1,rp:1
[3/0]aba48lf:35,lp:2,ls:11,rf:11,rp:1,rs:5,lsrp:1,lprs:1
[3/1]abb47lf:30,lp:12,ls:5,rf:19,rp:13,rs:4,re:1,lprp:10,lsrp:5,lprs:3
[3/2]bab46lf:46,rf:15
[3/3]bba25lf:25,rf:9
[3/4]bbb24lf:24,rf:36,rs:6,a:2
[3/5]aab7lf:5,lp:2,rf:1,rp:1
[3/6]baa3lf:3,a:12
[4/0]baba41lf:30,ls:11,rf:10,rs:5
[4/1]bbab25lf:25,rf:9
[4/2]abab23lf:21,lp:2,rf:6,rp:1
[4/3]babb21lf:16,ls:5,rf:5,rs:3,a:1
[4/4]abbb20lf:10,lp:10,rf:11,rp:11,rs:1,re:1,lprp:7,a:2
[4/5]abba17lf:15,lp:2,rf:4,rp:1
[4/6]bbbb14lf:14,rf:25,rs:5,a:4
[5/0]ababa25lf:14,ls:11,rf:5,rs:5
[5/1]abbab17lf:15,lp:2,rf:4,rp:1
[5/2]babab16lf:16,rf:5
[5/3]bbaba16lf:16,rf:5
[5/4]abbbb14lf:7,lp:7,rf:9,rp:9,rs:1,re:1,lprp:5,a:4
[5/5]ababb14lf:7,lp:2,ls:5,rf:1,rp:1,a:1
[5/6]babba11lf:11,rf:2,a:1
[6/0]bababa19lf:11,ls:8,rf:5,rs:5
[6/1]bbabab16lf:16,rf:5
[6/2]abbaba13lf:13
[6/3]babbab11lf:11,rf:2,a:1
[6/4]bababb10lf:5,ls:5,a:2
[6/5]bbabba9lf:9,rf:1,a:3
[6/6]abbbbb8lf:4,lp:4,rf:7,rp:7,rs:1,re:1,lprp:3,a:6
[7/0]bbababa19lf:11,ls:8,rf:5,rs:5
[7/1]abbabab13lf:13
[7/2]babbaba11lf:11,a:1
[7/3]bbababb10lf:5,ls:5,a:2
[7/4]bbabbab9lf:9,rf:1,a:3
[7/5]bbbabba7lf:7,a:5
[7/6]abbbbab6lf:3,lp:3,rf:1,rp:1,a:4

Considering [length 3 / frequency 1] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbababa=ab⟩.