| Back: | ⟨a, b | aabbabaab=ba⟩ |
|---|
Solved by morph:4/0,2/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: arenaTotalLimit
| # | Rule |
|---|---|
| 1. | aabbabaab ⇒ ba |
| 2. | aabbabba ⇒ bababaab |
| 3. | bababaababbabaab ⇒ aabbabbba |
| 4. | aabbabaaaabbabbba ⇒ baababaababbabaab |
| 5. | bababaababbabba ⇒ aabbabbbababaab |
| 6. | aabbaaabbabaaaabbabbbba ⇒ baabaababbabaababbabaab |
| 7. | baababaababbabaababbabaab ⇒ aabbabaaaabbabbbba |
| 8. | aabbabaaaabbabaaaabbabbbba ⇒ baaababaababbabaababbabaab |
| 9. | bababaababbabaaaabbabbba ⇒ aabbabbbaababaababbabaab |
| 10. | baababaababbabaababbabba ⇒ aabbabaaaabbabbbbababaab |
| 11. | baabaababbabaababbabaababbabaab ⇒ aabbaaabbabaaaabbabbbbba |
| ... |
Collecting factors up to length 7, frequency 4:
| Length 2: | [2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb |
|---|---|
| Length 3: | [3/0] bab, [3/1] aab, [3/2] bba, [3/3] aba |
| Length 4: | [4/0] abba, [4/1] baba, [4/2] baab, [4/3] bbab |
| Length 5: | [5/0] abbab, [5/1] babaa, [5/2] abaab, [5/3] babba |
| Length 6: | [6/0] babaab, [6/1] baabab, [6/2] aabbab, [6/3] bbabaa |
Considering [length 4 / frequency 0] abba=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | acbaab ⇒ ba |
| 2. | abba ⇒ c |
| 3. | baba ⇒ acbac |
| 4. | abbc ⇒ cbba |
| 5. | abacbac ⇒ cba |
| 6. | baacbac ⇒ acbacba |
| 7. | acbaccbac ⇒ bcba |
| 8. | acbaaacbac ⇒ baaba |
| 9. | acbaccbaab ⇒ bc |
| 10. | abbba ⇒ ccbaab |
| 11. | abacbba ⇒ cacbacab |
| 12. | acbacbba ⇒ babc |
| 13. | acbaccbba ⇒ bcacbacab |
| 14. | abbbc ⇒ ccbaccbaab |
| 15. | acbacbacbac ⇒ babcba |
| 16. | babcacbacab ⇒ acbbabc |
| 17. | abbbba ⇒ ccbaabcbaab |
| 18. | acbacbbba ⇒ babccbaab |
| 19. | babcbba ⇒ acbacbbc |
| 20. | acbacbbcbba ⇒ babcbbc |
| ... |
Collecting factors up to length 6, frequency 7:
| Length 2: | [2/0] ba, [2/1] ac, [2/2] cb, [2/3] ab, [2/4] bb, [2/5] bc, [2/6] aa |
|---|---|
| Length 3: | [3/0] acb, [3/1] bac, [3/2] bba, [3/3] cba, [3/4] abb, [3/5] cbb, [3/6] bab |
| Length 4: | [4/0] acba, [4/1] cbac, [4/2] cbba, [4/3] bacb, [4/4] bbba, [4/5] abbb, [4/6] babc |
| Length 5: | [5/0] acbac, [5/1] cbacb, [5/2] bcbba, [5/3] bacbb, [5/4] acbba, [5/5] abacb, [5/6] cbaab |
Considering [length 2 / frequency 0] ba=d.
Rewriting system is complete. See ⟨a, b | aabbabaab=ba⟩.