Morphocompletion for #4169 ⟨a, b | aabbaabba=ba

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. baabba ⇒ aabbba
2. aaaabbbba ⇒ ba
3. baabbba ⇒ aabbbba
4. aaaabbbbba ⇒ bba
5. baabbbba ⇒ aabbbbba
6. aaaabbbbbba ⇒ bbba
7. baabbbbba ⇒ aabbbbbba
8. aaaabbbbbbba ⇒ bbbba
9. baabbbbbba ⇒ aabbbbbbba
10. aaaabbbbbbbba ⇒ bbbbba
11. baabbbbbbba ⇒ aabbbbbbbba
12. aaaabbbbbbbbba ⇒ bbbbbba
13. baabbbbbbbba ⇒ aabbbbbbbbba
14. aaaabbbbbbbbbba ⇒ bbbbbbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ba, [2/2] aa, [2/3] ab
Length 3:[3/0] bbb, [3/1] bba, [3/2] aaa, [3/3] abb, [3/4] baa, [3/5] aab
Length 4:[4/0] bbbb, [4/1] bbba, [4/2] baab, [4/3] aabb, [4/4] aaaa, [4/5] abbb, [4/6] aaab
Length 5:[5/0] bbbbb, [5/1] bbbba, [5/2] baabb, [5/3] aaaab, [5/4] aabbb, [5/5] abbbb, [5/6] aaabb
Length 6:[6/0] bbbbbb, [6/1] bbbbba, [6/2] aaaabb, [6/3] baabbb, [6/4] aabbbb, [6/5] abbbbb, [6/6] aaabbb
Length 7:[7/0] bbbbbba, [7/1] aaaabbb, [7/2] bbbbbbb, [7/3] baabbbb, [7/4] aabbbbb, [7/5] abbbbbb, [7/6] aaabbbb

Considering [length 7 / frequency 0] bbbbbba=c.

Step 2

Rewriting system is complete. See a, b | aabbaabba=ba.