| Back: | ⟨a, b | aabbaabba=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabbab ⇒ ababba |
| 2. | ababbab ⇒ abbabba |
| 3. | aabbaabba ⇒ ab |
| 4. | abbabbab ⇒ abbbabba |
| 5. | ababbaabba ⇒ abb |
| 6. | aabbbabba ⇒ abbabbaab |
| 7. | aabbaabbb ⇒ abbbaabba |
| 8. | abbbabbab ⇒ abbbbabba |
| 9. | abbabbaabba ⇒ abbb |
| 10. | abbabbaaabba ⇒ aabbb |
| 11. | abbabbaaaabba ⇒ aaabbb |
| 12. | abbbabbaabba ⇒ abbbb |
| 13. | abbbabbaaabba ⇒ ababbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 48 | lf:35,lp:9,ls:4,rf:21,rp:11,rs:2,re:1,lprp:7,lsrp:4 |
|---|---|---|---|
| [2/1] | ba | 38 | lf:30,ls:8,rf:13,rs:5 |
| [2/2] | bb | 35 | lf:34,ls:1,rf:27,rs:6 |
| [2/3] | aa | 20 | lf:16,lp:4,rf:5,rp:2 |
| [3/0] | abb | 36 | lf:29,lp:7,rf:17,rp:8,rs:1,re:1,lprp:4 |
| [3/1] | bba | 36 | lf:28,ls:8,rf:11,rs:5 |
| [3/2] | bab | 18 | lf:14,ls:4,rf:6,a:1 |
| [3/3] | aab | 16 | lf:12,lp:4,rf:4,rp:1,rs:1,lprs:1 |
| [3/4] | baa | 8 | lf:8,rf:2 |
| [3/5] | bbb | 6 | lf:5,ls:1,rf:10,rs:5,a:4 |
| [3/6] | aba | 4 | lf:2,lp:2,rf:2,rp:2,a:1 |
| [4/0] | abba | 36 | lf:24,lp:4,ls:8,rf:8,rp:2,rs:5,lsrp:1,lprs:1 |
| [4/1] | bbab | 16 | lf:12,ls:4,rf:4,a:1 |
| [4/2] | aabb | 16 | lf:12,lp:4,rf:3,rp:1 |
| [4/3] | babb | 10 | lf:10,rf:6,a:1 |
| [4/4] | abbb | 9 | lf:5,lp:3,ls:1,rf:8,rp:5,rs:4,re:1,lprp:2,lsrp:1,lprs:1,a:4 |
| [4/5] | bbaa | 8 | lf:8,rf:2 |
| [4/6] | baab | 5 | lf:5,rf:2,rs:1 |
| [5/0] | aabba | 20 | lf:10,lp:3,ls:7,rf:1,rs:1,lprs:1 |
| [5/1] | abbab | 16 | lf:8,lp:4,ls:4,rf:2,rp:2,lsrp:1,a:1 |
| [5/2] | babba | 11 | lf:10,ls:1,rf:5,rs:4,a:1 |
| [5/3] | bbabb | 8 | lf:8,rf:4,a:3 |
| [5/4] | abbaa | 8 | lf:8,rf:1 |
| [5/5] | abbba | 7 | lf:4,lp:3,rf:2,rp:2,a:5 |
| [5/6] | baabb | 5 | lf:5,rf:1 |
| [6/0] | bbabba | 9 | lf:8,ls:1,rf:4,rs:3,a:3 |
| [6/1] | abbabb | 8 | lf:4,lp:4,rf:2,rp:2,a:3 |
| [6/2] | baabba | 8 | lf:4,ls:4,rf:1,rs:1 |
| [6/3] | abbbab | 7 | lf:4,lp:3,rf:1,rp:1,a:5 |
| [6/4] | babbab | 6 | lf:3,ls:3,a:3 |
| [6/5] | babbaa | 6 | lf:6,rf:1,a:2 |
| [6/6] | aaabba | 6 | lf:3,ls:3,a:7 |
| [7/0] | abbabba | 8 | lf:4,lp:4,rf:2,rp:2,rs:1,re:1,a:3 |
| [7/1] | bbaabba | 8 | lf:4,ls:4,rf:1,rs:1 |
| [7/2] | abbbabb | 7 | lf:4,lp:3,rf:1,rp:1,a:5 |
| [7/3] | bbbabba | 5 | lf:4,ls:1,rf:2,rs:2,a:5 |
| [7/4] | abbaabb | 5 | lf:5 |
| [7/5] | bbabbaa | 5 | lf:5,rf:1,a:4 |
| [7/6] | bbabbab | 4 | lf:2,ls:2,a:5 |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | aabbaabba=ab⟩.