Morphocompletion for #4168 ⟨a, b | aabbaabba=ab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbab ⇒ ababba
2. ababbab ⇒ abbabba
3. aabbaabba ⇒ ab
4. abbabbab ⇒ abbbabba
5. ababbaabba ⇒ abb
6. aabbbabba ⇒ abbabbaab
7. aabbaabbb ⇒ abbbaabba
8. abbbabbab ⇒ abbbbabba
9. abbabbaabba ⇒ abbb
10. abbabbaaabba ⇒ aabbb
11. abbabbaaaabba ⇒ aaabbb
12. abbbabbaabba ⇒ abbbb
13. abbbabbaaabba ⇒ ababbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] bb, [2/3] aa
Length 3:[3/0] abb, [3/1] bba, [3/2] bab, [3/3] aab, [3/4] baa, [3/5] bbb, [3/6] aba
Length 4:[4/0] abba, [4/1] bbab, [4/2] aabb, [4/3] babb, [4/4] abbb, [4/5] bbaa, [4/6] baab
Length 5:[5/0] aabba, [5/1] abbab, [5/2] babba, [5/3] bbabb, [5/4] abbaa, [5/5] abbba, [5/6] baabb
Length 6:[6/0] bbabba, [6/1] abbabb, [6/2] baabba, [6/3] abbbab, [6/4] babbab, [6/5] babbaa, [6/6] aaabba
Length 7:[7/0] abbabba, [7/1] bbaabba, [7/2] abbbabb, [7/3] bbbabba, [7/4] abbaabb, [7/5] bbabbaa, [7/6] bbabbab

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See a, b | aabbaabba=ab.