Morphocompletion for #4157 ⟨a, b | aabbaaaba=ba

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaabbaba ⇒ ba
2. bbaaaba ⇒ aabbaba
3. aaaabbabba ⇒ bba
4. bbaaabba ⇒ aabbabba
5. aaaabbabbba ⇒ bbba
6. bbaaabbba ⇒ aabbabbba
7. aaaabbabbbba ⇒ bbbba
8. bbaaabbbba ⇒ aabbabbbba
9. aaaabbabbbbba ⇒ bbbbba
10. bbaaabbbbba ⇒ aabbabbbbba
11. aaaabbabbbbbba ⇒ bbbbbba
12. bbaaabbbbbba ⇒ aabbabbbbbba
13. aaaabbabbbbbbba ⇒ bbbbbbba
14. bbaaabbbbbbba ⇒ aabbabbbbbbba
15. aaaabbabbbbbbbba ⇒ bbbbbbbba
16. aaaabbabbbbbbbbba ⇒ bbbbbbbbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] aa, [2/2] ba, [2/3] ab
Length 3:[3/0] bba, [3/1] bbb, [3/2] aaa, [3/3] abb, [3/4] aab, [3/5] bab, [3/6] baa
Length 4:[4/0] bbbb, [4/1] bbba, [4/2] aaaa, [4/3] aaab, [4/4] aabb, [4/5] bbaa, [4/6] abba
Length 5:[5/0] bbbbb, [5/1] bbbba, [5/2] aaaab, [5/3] aaabb, [5/4] bbaaa, [5/5] aabba, [5/6] abbbb
Length 6:[6/0] aaaabb, [6/1] bbbbba, [6/2] bbaaab, [6/3] bbbbbb, [6/4] aaabba, [6/5] aabbab, [6/6] abbbbb
Length 7:[7/0] aaaabba, [7/1] bbbbbba, [7/2] bbaaabb, [7/3] aaabbab, [7/4] aabbabb, [7/5] bbbbbbb, [7/6] abbabbb

Considering [length 3 / frequency 0] bba=c.

Step 2

Rewriting system is complete. See a, b | aabbaaaba=ba.