Morphocompletion for #4157 ⟨a, b | aabbaaaba=ba⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaabbaba ⇒ ba
2. bbaaaba ⇒ aabbaba
3. aaaabbabba ⇒ bba
4. bbaaabba ⇒ aabbabba
5. aaaabbabbba ⇒ bbba
6. bbaaabbba ⇒ aabbabbba
7. aaaabbabbbba ⇒ bbbba
8. bbaaabbbba ⇒ aabbabbbba
9. aaaabbabbbbba ⇒ bbbbba
10. bbaaabbbbba ⇒ aabbabbbbba
11. aaaabbabbbbbba ⇒ bbbbbba
12. bbaaabbbbbba ⇒ aabbabbbbbba
13. aaaabbabbbbbbba ⇒ bbbbbbba
14. bbaaabbbbbbba ⇒ aabbabbbbbbba
15. aaaabbabbbbbbbba ⇒ bbbbbbbba
16. aaaabbabbbbbbbbba ⇒ bbbbbbbbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb80lf:73,lp:7,rf:64,rp:8,a:2
[2/1]aa50lf:41,lp:9,rf:7,rp:7,a:2
[2/2]ba48lf:32,ls:16,rf:23,rp:1,rs:16,re:1,lsrp:1,lsrs:16,a:2
[2/3]ab25lf:25,rf:14,a:2
[3/0]bba51lf:30,lp:7,ls:14,rf:21,rp:1,rs:14,re:1,lsrp:1,lprs:6,lsrs:14,a:2
[3/1]bbb43lf:43,rf:43,rp:7,a:2
[3/2]aaa34lf:25,lp:9,a:2
[3/3]abb23lf:23,rf:13,a:2
[3/4]aab16lf:16,rf:7,rp:7,a:2
[3/5]bab9lf:9,rf:7,a:2
[3/6]baa7lf:7,a:3
[4/0]bbbb31lf:31,rf:31,rp:6,a:9
[4/1]bbba24lf:12,ls:12,rf:12,rp:1,rs:12,re:1,lsrp:1,lsrs:12,a:2
[4/2]aaaa18lf:9,lp:9,a:2
[4/3]aaab16lf:16,a:2
[4/4]aabb15lf:15,rf:7,rp:7,a:2
[4/5]bbaa14lf:7,lp:7,a:3
[4/6]abba13lf:11,ls:2,rf:8,rs:1,lsrs:1,a:2
[5/0]bbbbb21lf:21,rf:21,rp:5,a:10
[5/1]bbbba20lf:10,ls:10,rf:10,rp:1,rs:10,re:1,lsrp:1,lsrs:10,a:9
[5/2]aaaab18lf:9,lp:9,a:2
[5/3]aaabb15lf:15,a:2
[5/4]bbaaa14lf:7,lp:7,a:3
[5/5]aabba11lf:10,ls:1,rf:7,rp:7,lsrp:1,a:2
[5/6]abbbb10lf:10,rf:4,a:9
[6/0]aaaabb18lf:9,lp:9,a:2
[6/1]bbbbba16lf:8,ls:8,rf:8,rp:1,rs:8,re:1,lsrp:1,lsrs:8,a:10
[6/2]bbaaab14lf:7,lp:7,a:3
[6/3]bbbbbb13lf:13,rf:13,rp:4,a:11
[6/4]aaabba11lf:10,ls:1,a:2
[6/5]aabbab9lf:9,rf:7,rp:7,a:2
[6/6]abbbbb8lf:8,rf:3,a:10
[7/0]aaaabba18lf:9,lp:9,a:2
[7/1]bbbbbba12lf:6,ls:6,rf:6,rp:1,rs:6,re:1,lsrp:1,lsrs:6,a:11
[7/2]bbaaabb12lf:6,lp:6,a:4
[7/3]aaabbab9lf:9,a:2
[7/4]aabbabb8lf:8,rf:6,rp:6,a:2
[7/5]bbbbbbb7lf:7,rf:7,rp:3,a:18
[7/6]abbabbb7lf:7,rf:5,a:2

Considering [length 3 / frequency 0] bba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbaaaba=ba⟩.