Morphocompletion for #4156 ⟨a, b | aabbaaaba=ab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbaaaba ⇒ ab
2. ababbaaaba ⇒ abb
3. aabbaaabb ⇒ abbbaaaba
4. abbbaaabaaaaba ⇒ aabbaab
5. abbabbaaaba ⇒ abbb
6. ababbaaabb ⇒ abbbbaaaba
7. abbbbaaabaaaaba ⇒ ababbaab
8. abbbabbaaaba ⇒ abbbb
9. abbabbaaabb ⇒ abbbbbaaaba
10. abbbbbaaabaaaaba ⇒ abbabbaab
11. abbbbabbaaaba ⇒ abbbbb
12. abbbabbaaabb ⇒ abbbbbbaaaba
13. abbbbbabbaaaba ⇒ abbbbbb
14. abbbbabbaaabb ⇒ abbbbbbbaaaba
15. abbbbbbabbaaaba ⇒ abbbbbbb
16. abbbbbbbabbaaaba ⇒ abbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]ab60lf:46,lp:14,rf:26,rp:15,rs:4,re:1,lprp:13,lprs:3
[2/1]bb59lf:54,ls:5,rf:52,rs:7
[2/2]ba52lf:41,ls:11,rf:15,rs:5
[2/3]aa45lf:43,lp:2,rf:14,rp:1
[3/0]abb47lf:30,lp:12,ls:5,rf:16,rp:13,rs:1,re:1,lprp:10,lsrp:5
[3/1]aba29lf:16,lp:2,ls:11,rf:6,rp:1,rs:5,lsrp:1,lprs:1
[3/2]bba25lf:25,rf:9
[3/3]bbb24lf:24,rf:36,rs:6,a:2
[3/4]aab23lf:21,lp:2,rf:9,rp:1,rs:3
[3/5]aaa22lf:22,rf:5
[3/6]baa19lf:19,rf:8
[4/0]aaba25lf:14,ls:11,rf:5,rs:5
[4/1]abbb20lf:10,lp:10,rf:11,rp:11,rs:1,re:1,lprp:7,a:2
[4/2]aaab19lf:19,rf:5
[4/3]baaa19lf:19,rf:5
[4/4]abba17lf:15,lp:2,rf:4,rp:1
[4/5]bbaa16lf:16,rf:8
[4/6]bbbb14lf:14,rf:25,rs:5,a:4
[5/0]aaaba25lf:14,ls:11,rf:5,rs:5
[5/1]baaab16lf:16,rf:5
[5/2]bbaaa16lf:16,rf:5
[5/3]abbbb14lf:7,lp:7,rf:9,rp:9,rs:1,re:1,lprp:5,a:4
[5/4]abbaa13lf:13,rf:3
[5/5]babba11lf:11,rf:2,a:1
[5/6]aaabb10lf:5,ls:5,a:2
[6/0]baaaba19lf:11,ls:8,rf:5,rs:5
[6/1]bbaaab16lf:16,rf:5
[6/2]abbaaa13lf:13
[6/3]babbaa11lf:11,rf:2,a:1
[6/4]baaabb10lf:5,ls:5,a:2
[6/5]bbabba9lf:9,rf:1,a:3
[6/6]abbbbb8lf:4,lp:4,rf:7,rp:7,rs:1,re:1,lprp:3,a:6
[7/0]bbaaaba19lf:11,ls:8,rf:5,rs:5
[7/1]abbaaab13lf:13
[7/2]babbaaa11lf:11,a:1
[7/3]bbaaabb10lf:5,ls:5,a:2
[7/4]bbabbaa9lf:9,rf:1,a:3
[7/5]bbbabba7lf:7,a:5
[7/6]baaaaba6lf:3,ls:3,a:12

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbaaaba=ab⟩.