Morphocompletion for #4148 ⟨a, b | aababbbba=ab

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aababbbba ⇒ ab
2. abbabbbba ⇒ aababbbbb
3. abababbbba ⇒ abb
4. abbbabbbba ⇒ abababbbbb
5. abbababbbba ⇒ abbb
6. abbbbabbbba ⇒ abbababbbbb
7. abbbababbbba ⇒ abbbb
8. aababbababbbbb ⇒ abbbbba
9. abbbbbabbbba ⇒ abbbababbbbb
10. abbbbababbbba ⇒ abbbbb
11. abababbababbbbb ⇒ abbbbbba
12. abbbbbbabbbba ⇒ abbbbababbbbb
13. abbbbbababbbba ⇒ abbbbbb
14. abbababbababbbbb ⇒ abbbbbbba
15. abbbbbbababbbba ⇒ abbbbbbb
16. abbbababbababbbbb ⇒ abbbbbbbba
17. abbbbbbbababbbba ⇒ abbbbbbbb
18. abbbbbbbbababbbba ⇒ abbbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:[3/0] bbb, [3/1] abb, [3/2] bba, [3/3] bab, [3/4] aba, [3/5] aab
Length 4:[4/0] bbbb, [4/1] abbb, [4/2] bbba, [4/3] babb, [4/4] abab, [4/5] bbab, [4/6] baba
Length 5:[5/0] bbbba, [5/1] abbbb, [5/2] bbbbb, [5/3] babbb, [5/4] ababb, [5/5] babab, [5/6] bbaba
Length 6:[6/0] abbbba, [6/1] abbbbb, [6/2] babbbb, [6/3] bababb, [6/4] bbabab, [6/5] ababbb, [6/6] bbbbab
Length 7:[7/0] babbbba, [7/1] bbababb, [7/2] ababbbb, [7/3] bababbb, [7/4] babbbbb, [7/5] abbbbbb, [7/6] abbabab

Considering [length 5 / frequency 0] bbbba=c.

Step 2

Rewriting system is complete. See a, b | aababbbba=ab.