| Back: | ⟨a, b | aababbbba=ab⟩ |
|---|
Solved by morph:5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aababbbba ⇒ ab |
| 2. | abbabbbba ⇒ aababbbbb |
| 3. | abababbbba ⇒ abb |
| 4. | abbbabbbba ⇒ abababbbbb |
| 5. | abbababbbba ⇒ abbb |
| 6. | abbbbabbbba ⇒ abbababbbbb |
| 7. | abbbababbbba ⇒ abbbb |
| 8. | aababbababbbbb ⇒ abbbbba |
| 9. | abbbbbabbbba ⇒ abbbababbbbb |
| 10. | abbbbababbbba ⇒ abbbbb |
| 11. | abababbababbbbb ⇒ abbbbbba |
| 12. | abbbbbbabbbba ⇒ abbbbababbbbb |
| 13. | abbbbbababbbba ⇒ abbbbbb |
| 14. | abbababbababbbbb ⇒ abbbbbbba |
| 15. | abbbbbbababbbba ⇒ abbbbbbb |
| 16. | abbbababbababbbbb ⇒ abbbbbbbba |
| 17. | abbbbbbbababbbba ⇒ abbbbbbbb |
| 18. | abbbbbbbbababbbba ⇒ abbbbbbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | bb | 112 | lf:108,ls:4,rf:84,rs:13 |
|---|---|---|---|
| [2/1] | ab | 71 | lf:55,lp:16,rf:27,rp:17,rs:1,re:1,lprp:15 |
| [2/2] | ba | 65 | lf:51,ls:14,rf:13,rs:4 |
| [2/3] | aa | 4 | lf:2,lp:2,rf:1,rp:1 |
| [3/0] | bbb | 76 | lf:72,ls:4,rf:64,rs:12 |
| [3/1] | abb | 50 | lf:36,lp:14,rf:20,rp:15,rs:1,re:1,lprp:12 |
| [3/2] | bba | 46 | lf:32,ls:14,rf:7,rs:4 |
| [3/3] | bab | 37 | lf:37,rf:9 |
| [3/4] | aba | 21 | lf:19,lp:2,rf:6,rp:1 |
| [3/5] | aab | 4 | lf:2,lp:2,rf:1,rp:1 |
| [4/0] | bbbb | 47 | lf:43,ls:4,rf:46,rs:11 |
| [4/1] | abbb | 40 | lf:29,lp:11,rf:18,rp:13,rs:1,re:1,lprp:9 |
| [4/2] | bbba | 39 | lf:25,ls:14,rf:6,rs:4 |
| [4/3] | babb | 22 | lf:22,rf:5 |
| [4/4] | abab | 21 | lf:19,lp:2,rf:6,rp:1 |
| [4/5] | bbab | 18 | lf:18,rf:3,a:2 |
| [4/6] | baba | 15 | lf:15,rf:4,a:1 |
| [5/0] | bbbba | 36 | lf:22,ls:14,rf:5,rs:4 |
| [5/1] | abbbb | 34 | lf:26,lp:8,rf:16,rp:11,rs:1,re:1,lprp:6 |
| [5/2] | bbbbb | 21 | lf:17,ls:4,rf:30,rs:10,a:4 |
| [5/3] | babbb | 18 | lf:18,rf:5 |
| [5/4] | ababb | 17 | lf:17,rf:5 |
| [5/5] | babab | 15 | lf:15,rf:4,a:1 |
| [5/6] | bbaba | 13 | lf:13,rf:3,a:2 |
| [6/0] | abbbba | 32 | lf:16,lp:2,ls:14,rf:1,rp:1,lsrp:1 |
| [6/1] | abbbbb | 20 | lf:10,lp:6,ls:4,rf:14,rp:9,rs:6,re:1,lprp:4,lsrp:4,lprs:2,a:4 |
| [6/2] | babbbb | 18 | lf:18,rf:5 |
| [6/3] | bababb | 15 | lf:15,rf:4,a:1 |
| [6/4] | bbabab | 13 | lf:13,rf:3,a:2 |
| [6/5] | ababbb | 13 | lf:13,rf:5 |
| [6/6] | bbbbab | 8 | lf:8,rf:1,a:4 |
| [7/0] | babbbba | 28 | lf:14,ls:14 |
| [7/1] | bbababb | 13 | lf:13,rf:3,a:2 |
| [7/2] | ababbbb | 13 | lf:13,rf:5 |
| [7/3] | bababbb | 12 | lf:12,rf:4,a:1 |
| [7/4] | babbbbb | 8 | lf:4,ls:4,rf:5,rs:5,a:8 |
| [7/5] | abbbbbb | 8 | lf:4,lp:4,rf:7,rp:7,rs:1,re:1,lprp:3,a:5 |
| [7/6] | abbabab | 8 | lf:6,lp:2,rf:1,rp:1,a:2 |
Considering [length 5 / frequency 0] bbbba=c.
Rewriting system is complete. See ⟨a, b | aababbbba=ab⟩.