| Back: | ⟨a, b | aababbbba=ab⟩ |
|---|
Solved by morph:5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aababbbba ⇒ ab |
| 2. | abbabbbba ⇒ aababbbbb |
| 3. | abababbbba ⇒ abb |
| 4. | abbbabbbba ⇒ abababbbbb |
| 5. | abbababbbba ⇒ abbb |
| 6. | abbbbabbbba ⇒ abbababbbbb |
| 7. | abbbababbbba ⇒ abbbb |
| 8. | aababbababbbbb ⇒ abbbbba |
| 9. | abbbbbabbbba ⇒ abbbababbbbb |
| 10. | abbbbababbbba ⇒ abbbbb |
| 11. | abababbababbbbb ⇒ abbbbbba |
| 12. | abbbbbbabbbba ⇒ abbbbababbbbb |
| 13. | abbbbbababbbba ⇒ abbbbbb |
| 14. | abbababbababbbbb ⇒ abbbbbbba |
| 15. | abbbbbbababbbba ⇒ abbbbbbb |
| 16. | abbbababbababbbbb ⇒ abbbbbbbba |
| 17. | abbbbbbbababbbba ⇒ abbbbbbbb |
| 18. | abbbbbbbbababbbba ⇒ abbbbbbbbb |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa |
|---|---|
| Length 3: | [3/0] bbb, [3/1] abb, [3/2] bba, [3/3] bab, [3/4] aba, [3/5] aab |
| Length 4: | [4/0] bbbb, [4/1] abbb, [4/2] bbba, [4/3] babb, [4/4] abab, [4/5] bbab, [4/6] baba |
| Length 5: | [5/0] bbbba, [5/1] abbbb, [5/2] bbbbb, [5/3] babbb, [5/4] ababb, [5/5] babab, [5/6] bbaba |
| Length 6: | [6/0] abbbba, [6/1] abbbbb, [6/2] babbbb, [6/3] bababb, [6/4] bbabab, [6/5] ababbb, [6/6] bbbbab |
| Length 7: | [7/0] babbbba, [7/1] bbababb, [7/2] ababbbb, [7/3] bababbb, [7/4] babbbbb, [7/5] abbbbbb, [7/6] abbabab |
Considering [length 5 / frequency 0] bbbba=c.
Rewriting system is complete. See ⟨a, b | aababbbba=ab⟩.