| Back: | ⟨a, b | aababbbaa=ba⟩ |
|---|
Solved by morph:4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aababbbaa ⇒ ba |
| 2. | aababbbaba ⇒ bba |
| 3. | bababbbaa ⇒ aababbbba |
| 4. | aababbbabba ⇒ bbba |
| 5. | bababbbaba ⇒ aababbbbba |
| 6. | aababbbabbba ⇒ bbbba |
| 7. | bababbbabba ⇒ aababbbbbba |
| 8. | aababbbabbbba ⇒ bbbbba |
| 9. | aababbaababbbba ⇒ bbabbbaa |
| 10. | bababbbabbba ⇒ aababbbbbbba |
| 11. | aababbbabbbbba ⇒ bbbbbba |
| 12. | aababbaababbbbba ⇒ bbabbbaba |
| 13. | bababbbabbbba ⇒ aababbbbbbbba |
| 14. | aababbbabbbbbba ⇒ bbbbbbba |
| 15. | aababbaababbbbbba ⇒ bbabbbabba |
| 16. | aababbbabbbbbbba ⇒ bbbbbbbba |
| 17. | aababbbabbbbbbbba ⇒ bbbbbbbbba |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | bb | 77 | lf:77,rf:71,rp:11 |
|---|---|---|---|
| [2/1] | ba | 77 | lf:57,lp:5,ls:15,rf:27,rp:1,rs:16,re:1,lprs:5,lsrs:14 |
| [2/2] | ab | 52 | lf:52,rf:15 |
| [2/3] | aa | 31 | lf:17,lp:12,ls:2,rf:6,rp:5,rs:1,lsrp:1,lprs:1 |
| [3/0] | bbb | 47 | lf:47,rf:51,rp:7 |
| [3/1] | bba | 43 | lf:30,ls:13,rf:20,rp:4,rs:14,re:1,lsrp:3,lsrs:11 |
| [3/2] | bab | 42 | lf:37,lp:5,rf:10 |
| [3/3] | abb | 30 | lf:30,rf:9 |
| [3/4] | aab | 27 | lf:15,lp:12,rf:5,rp:5 |
| [3/5] | aba | 24 | lf:22,ls:2,rf:6,rs:1 |
| [3/6] | baa | 7 | lf:5,ls:2,rf:1,rs:1 |
| [4/0] | bbba | 36 | lf:25,ls:11,rf:15,rp:1,rs:12,re:1,lsrs:8 |
| [4/1] | babb | 30 | lf:30,rf:9 |
| [4/2] | aaba | 27 | lf:15,lp:12,rf:5,rp:5 |
| [4/3] | abbb | 25 | lf:25,rf:8 |
| [4/4] | bbbb | 22 | lf:22,rf:36,rp:6,a:1 |
| [4/5] | abab | 20 | lf:20,rf:5 |
| [4/6] | baba | 14 | lf:7,lp:5,ls:2,rf:1,rs:1,a:1 |
| [5/0] | aabab | 27 | lf:15,lp:12,rf:5,rp:5 |
| [5/1] | babbb | 25 | lf:25,rf:8 |
| [5/2] | ababb | 20 | lf:20,rf:5 |
| [5/3] | bbbba | 18 | lf:9,ls:9,rf:11,rp:1,rs:11,re:1,lsrs:6,a:1 |
| [5/4] | abbba | 18 | lf:16,ls:2,rf:3 |
| [5/5] | bbbbb | 13 | lf:13,rf:25,rp:5,a:3 |
| [5/6] | bbbab | 12 | lf:12,rf:2,a:2 |
| [6/0] | aababb | 27 | lf:15,lp:12,rf:5,rp:5 |
| [6/1] | babbba | 18 | lf:16,ls:2,rf:3 |
| [6/2] | ababbb | 17 | lf:17,rf:5 |
| [6/3] | bbbbba | 12 | lf:6,ls:6,rf:9,rp:1,rs:9,re:1,lsrs:4,a:3 |
| [6/4] | abbbab | 12 | lf:12,rf:2,a:2 |
| [6/5] | bbbabb | 10 | lf:10,rf:1,a:4 |
| [6/6] | bababb | 10 | lf:5,lp:5,a:1 |
| [7/0] | aababbb | 21 | lf:12,lp:9,rf:5,rp:5 |
| [7/1] | ababbba | 14 | lf:14 |
| [7/2] | babbbab | 12 | lf:12,rf:2,a:2 |
| [7/3] | abbbabb | 10 | lf:10,rf:1,a:4 |
| [7/4] | bababbb | 10 | lf:5,lp:5,a:1 |
| [7/5] | bbbbbba | 8 | lf:4,ls:4,rf:7,rp:1,rs:7,re:1,lsrs:3,a:6 |
| [7/6] | bbbabbb | 8 | lf:8,a:5 |
Considering [length 4 / frequency 0] bbba=c.
Rewriting system is complete. See ⟨a, b | aababbbaa=ba⟩.