| Back: | ⟨a, b | aababbbaa=ba⟩ |
|---|
Solved by morph:4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aababbbaa ⇒ ba |
| 2. | aababbbaba ⇒ bba |
| 3. | bababbbaa ⇒ aababbbba |
| 4. | aababbbabba ⇒ bbba |
| 5. | bababbbaba ⇒ aababbbbba |
| 6. | aababbbabbba ⇒ bbbba |
| 7. | bababbbabba ⇒ aababbbbbba |
| 8. | aababbbabbbba ⇒ bbbbba |
| 9. | aababbaababbbba ⇒ bbabbbaa |
| 10. | bababbbabbba ⇒ aababbbbbbba |
| 11. | aababbbabbbbba ⇒ bbbbbba |
| 12. | aababbaababbbbba ⇒ bbabbbaba |
| 13. | bababbbabbbba ⇒ aababbbbbbbba |
| 14. | aababbbabbbbbba ⇒ bbbbbbba |
| 15. | aababbaababbbbbba ⇒ bbabbbabba |
| 16. | aababbbabbbbbbba ⇒ bbbbbbbba |
| 17. | aababbbabbbbbbbba ⇒ bbbbbbbbba |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] bb, [2/1] ba, [2/2] ab, [2/3] aa |
|---|---|
| Length 3: | [3/0] bbb, [3/1] bba, [3/2] bab, [3/3] abb, [3/4] aab, [3/5] aba, [3/6] baa |
| Length 4: | [4/0] bbba, [4/1] babb, [4/2] aaba, [4/3] abbb, [4/4] bbbb, [4/5] abab, [4/6] baba |
| Length 5: | [5/0] aabab, [5/1] babbb, [5/2] ababb, [5/3] bbbba, [5/4] abbba, [5/5] bbbbb, [5/6] bbbab |
| Length 6: | [6/0] aababb, [6/1] babbba, [6/2] ababbb, [6/3] bbbbba, [6/4] abbbab, [6/5] bbbabb, [6/6] bababb |
| Length 7: | [7/0] aababbb, [7/1] ababbba, [7/2] babbbab, [7/3] abbbabb, [7/4] bababbb, [7/5] bbbbbba, [7/6] bbbabbb |
Considering [length 4 / frequency 0] bbba=c.
Rewriting system is complete. See ⟨a, b | aababbbaa=ba⟩.