| Back: | ⟨a, b | aababbbaa=ab⟩ |
|---|
Solved by morph:5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aababbbaa ⇒ ab |
| 2. | abababbbaa ⇒ abb |
| 3. | aababbbab ⇒ abbabbbaa |
| 4. | abbababbbaa ⇒ abbb |
| 5. | abababbbab ⇒ abbbabbbaa |
| 6. | abbbababbbaa ⇒ abbbb |
| 7. | abbababbbab ⇒ abbbbabbbaa |
| 8. | abbbbababbbaa ⇒ abbbbb |
| 9. | abbbababbbab ⇒ abbbbbabbbaa |
| 10. | abbabbbaaabbbaa ⇒ aababbbb |
| 11. | abbbbbababbbaa ⇒ abbbbbb |
| 12. | abbbbababbbab ⇒ abbbbbbabbbaa |
| 13. | abbbabbbaaabbbaa ⇒ abababbbb |
| 14. | abbbbbbababbbaa ⇒ abbbbbbb |
| 15. | abbbbbbbababbbaa ⇒ abbbbbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 66 | lf:48,lp:13,ls:5,rf:23,rp:14,rs:1,re:1,lprp:12,lsrp:5 |
|---|---|---|---|
| [2/1] | bb | 64 | lf:64,rf:59,rs:9 |
| [2/2] | ba | 43 | lf:43,rf:13 |
| [2/3] | aa | 28 | lf:16,lp:2,ls:10,rf:6,rp:1,rs:5,lsrp:1,lprs:1 |
| [3/0] | abb | 39 | lf:28,lp:11,rf:19,rp:12,rs:1,re:1,lprp:9 |
| [3/1] | bbb | 36 | lf:36,rf:40,rs:8 |
| [3/2] | bab | 36 | lf:31,ls:5,rf:8 |
| [3/3] | bba | 28 | lf:28,rf:10 |
| [3/4] | baa | 22 | lf:12,ls:10,rf:5,rs:5 |
| [3/5] | aba | 17 | lf:15,lp:2,rf:3,rp:1 |
| [3/6] | aab | 6 | lf:4,lp:2,rf:1,rp:1 |
| [4/0] | abbb | 33 | lf:25,lp:8,rf:17,rp:10,rs:1,re:1,lprp:7 |
| [4/1] | bbba | 25 | lf:25,rf:9 |
| [4/2] | bbaa | 22 | lf:12,ls:10,rf:5,rs:5 |
| [4/3] | bbab | 21 | lf:16,ls:5,rf:5,a:1 |
| [4/4] | abab | 17 | lf:15,lp:2,rf:3,rp:1 |
| [4/5] | babb | 15 | lf:15,rf:7 |
| [4/6] | bbbb | 11 | lf:11,rf:23,rs:7,a:5 |
| [5/0] | abbba | 23 | lf:20,lp:3,rf:6,rp:1 |
| [5/1] | bbbaa | 22 | lf:12,ls:10,rf:5,rs:5 |
| [5/2] | bbbab | 18 | lf:13,ls:5,rf:4,a:1 |
| [5/3] | babbb | 15 | lf:15,rf:7 |
| [5/4] | ababb | 13 | lf:13,rf:2 |
| [5/5] | babab | 11 | lf:11,rf:1,a:2 |
| [5/6] | abbbb | 10 | lf:5,lp:5,rf:10,rp:8,rs:3,re:1,lprp:5,a:5 |
| [6/0] | abbbaa | 22 | lf:12,ls:10,rf:5,rs:5 |
| [6/1] | abbbab | 16 | lf:8,lp:3,ls:5,rf:1,rp:1,lsrp:1,a:1 |
| [6/2] | babbba | 15 | lf:15,rf:5 |
| [6/3] | ababbb | 13 | lf:13,rf:2 |
| [6/4] | bababb | 11 | lf:11,rf:1,a:2 |
| [6/5] | bbabab | 9 | lf:9,a:3 |
| [6/6] | bbbaba | 7 | lf:7,a:5 |
| [7/0] | babbbaa | 18 | lf:10,ls:8,rf:5,rs:5 |
| [7/1] | ababbba | 13 | lf:13 |
| [7/2] | bababbb | 11 | lf:11,rf:1,a:2 |
| [7/3] | babbbab | 10 | lf:5,ls:5,a:1 |
| [7/4] | bbababb | 9 | lf:9,a:3 |
| [7/5] | bbbabab | 7 | lf:7,a:5 |
| [7/6] | bbbbaba | 5 | lf:5,a:6 |
Considering [length 5 / frequency 0] abbba=c.
Rewriting system is complete. See ⟨a, b | aababbbaa=ab⟩.