Morphocompletion for #4136 ⟨a, b | aababbaba=ab⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbaba ⇒ aababbb
2. aababbaba ⇒ ab
3. abbbbaba ⇒ abababbb
4. abbabbaba ⇒ aababbabb
5. abababbaba ⇒ abb
6. abbbbbaba ⇒ abbababbb
7. abbbabbaba ⇒ abababbabb
8. abbababbaba ⇒ abbb
9. abbbbbbaba ⇒ aababbbbbb
10. abbbbabbaba ⇒ abbababbabb
11. abbbbbbbaba ⇒ abababbbbbb
12. abbbbbabbaba ⇒ aababbbbbabb
13. abbbbbbbbaba ⇒ abbababbbbbb
14. abbbbbbabbaba ⇒ abababbbbbabb
15. abbbbbbbbbaba ⇒ aababbbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb59lf:59,rf:51,rs:14
[2/1]ba55lf:40,ls:15,rf:24
[2/2]ab54lf:40,lp:14,rf:39,rp:10,rs:1,re:1,lprp:9
[2/3]aa2lf:1,lp:1,rf:5,rp:5
[3/0]bbb38lf:38,rf:29,rs:8,a:3
[3/1]aba35lf:19,lp:1,ls:15,rf:16,rp:4,lsrp:4
[3/2]abb34lf:21,lp:13,rf:22,rp:5,rs:6,re:1,lprp:4,lprs:5
[3/3]bab25lf:25,rf:24
[3/4]bba21lf:21,rf:8
[3/5]aab2lf:1,lp:1,rf:5,rp:5
[4/0]baba32lf:17,ls:15,rf:7
[4/1]bbbb27lf:27,rf:19,rs:4,a:7
[4/2]abbb22lf:11,lp:11,rf:10,rp:1,rs:4,re:1,lprs:3,a:3
[4/3]bbab21lf:21,rf:8
[4/4]abba12lf:10,lp:2,rf:6,rp:3
[4/5]bbba11lf:11,rf:2,a:4
[4/6]babb8lf:8,rf:17,rs:5
[5/0]bbaba31lf:16,ls:15,rf:3
[5/1]bbbbb18lf:18,rf:13,rs:4,a:11
[5/2]abbbb18lf:9,lp:9,rf:6,a:7
[5/3]abbab12lf:10,lp:2,rf:6,rp:3
[5/4]bbbab11lf:11,rf:2,a:4
[5/5]bbbba9lf:9,rf:2,a:7
[5/6]babba8lf:8,rf:3
[6/0]abbaba18lf:9,lp:1,ls:8,rf:3,rp:3,lsrp:1
[6/1]abbbbb14lf:7,lp:7,rf:6,a:11
[6/2]bbbaba14lf:7,ls:7,a:6
[6/3]bbbbbb11lf:11,rf:7,rs:4,a:12
[6/4]bbbbab9lf:9,rf:2,a:7
[6/5]babbab8lf:8,rf:3
[6/6]bbbbba7lf:7,rf:2,a:11
[7/0]babbaba16lf:8,ls:8
[7/1]bbbbaba12lf:6,ls:6,a:7
[7/2]abbbbbb10lf:5,lp:5,rf:4,rs:3,lprs:3,a:12
[7/3]bbbbbab7lf:7,rf:2,a:11
[7/4]bbbbbbb6lf:6,rf:3,rs:1,a:13
[7/5]bbbbbba5lf:5,a:12
[7/6]bbabbab5lf:5,a:2

Considering [length 5 / frequency 0] bbaba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aababbaba=ab⟩.