Morphocompletion for #4136 ⟨a, b | aababbaba=ab

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbaba ⇒ aababbb
2. aababbaba ⇒ ab
3. abbbbaba ⇒ abababbb
4. abbabbaba ⇒ aababbabb
5. abababbaba ⇒ abb
6. abbbbbaba ⇒ abbababbb
7. abbbabbaba ⇒ abababbabb
8. abbababbaba ⇒ abbb
9. abbbbbbaba ⇒ aababbbbbb
10. abbbbabbaba ⇒ abbababbabb
11. abbbbbbbaba ⇒ abababbbbbb
12. abbbbbabbaba ⇒ aababbbbbabb
13. abbbbbbbbaba ⇒ abbababbbbbb
14. abbbbbbabbaba ⇒ abababbbbbabb
15. abbbbbbbbbaba ⇒ aababbbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ba, [2/2] ab, [2/3] aa
Length 3:[3/0] bbb, [3/1] aba, [3/2] abb, [3/3] bab, [3/4] bba, [3/5] aab
Length 4:[4/0] baba, [4/1] bbbb, [4/2] abbb, [4/3] bbab, [4/4] abba, [4/5] bbba, [4/6] babb
Length 5:[5/0] bbaba, [5/1] bbbbb, [5/2] abbbb, [5/3] abbab, [5/4] bbbab, [5/5] bbbba, [5/6] babba
Length 6:[6/0] abbaba, [6/1] abbbbb, [6/2] bbbaba, [6/3] bbbbbb, [6/4] bbbbab, [6/5] babbab, [6/6] bbbbba
Length 7:[7/0] babbaba, [7/1] bbbbaba, [7/2] abbbbbb, [7/3] bbbbbab, [7/4] bbbbbbb, [7/5] bbbbbba, [7/6] bbabbab

Considering [length 5 / frequency 0] bbaba=c.

Step 2

Rewriting system is complete. See a, b | aababbaba=ab.