Morphocompletion for #4128 ⟨a, b | aabababba=ab

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aabababba ⇒ ab
2. ababababba ⇒ abb
3. aabababbb ⇒ abbababba
4. abbabababba ⇒ abbb
5. ababababbb ⇒ abbbababba
6. abbbabababba ⇒ abbbb
7. abbabababbb ⇒ abbbbababba
8. abbbbabababba ⇒ abbbbb
9. abbbabababbb ⇒ abbbbbababba
10. abbbbbabababba ⇒ abbbbbb
11. abbbbabababbb ⇒ abbbbbbababba
12. abbbbbbabababba ⇒ abbbbbbb
13. abbbbbabababbb ⇒ abbbbbbbababba
14. abbbbbbbabababba ⇒ abbbbbbbb
15. abbbbbbabababbb ⇒ abbbbbbbbababba
16. abbbbbbbbabababba ⇒ abbbbbbbbb
17. abbbbbbbabababbb ⇒ abbbbbbbbbababba
18. abbbbbbbbbabababba ⇒ abbbbbbbbbb
19. abbbbbbbbbbabababba ⇒ abbbbbbbbbbb
20. abbbbbbbbbbbabababba ⇒ abbbbbbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:[3/0] bbb, [3/1] bab, [3/2] abb, [3/3] aba, [3/4] bba, [3/5] aab
Length 4:[4/0] bbbb, [4/1] abbb, [4/2] abab, [4/3] baba, [4/4] abba, [4/5] babb, [4/6] bbab
Length 5:[5/0] babab, [5/1] bbbbb, [5/2] abbbb, [5/3] babba, [5/4] ababa, [5/5] ababb, [5/6] babbb
Length 6:[6/0] bbbbbb, [6/1] ababab, [6/2] ababba, [6/3] abbbbb, [6/4] bababb, [6/5] bababa, [6/6] ababbb
Length 7:[7/0] bababba, [7/1] abababb, [7/2] bababab, [7/3] bbbbbbb, [7/4] abbbbbb, [7/5] bababbb, [7/6] bbababa

Considering [length 7 / frequency 0] bababba=c.

Step 2

Rewriting system is complete. See a, b | aabababba=ab.